equaivalence principle

Discussion in 'Physics & Math' started by ash64449, Apr 7, 2013.

  1. eram Sciengineer Valued Senior Member

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    Dude, force causes acceleration. -_-

    See, language barrier.
     
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  3. ash64449 Registered Senior Member

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    yes. Force causes acceleration. I asked what force the being should apply to make room accelerate so that the man inside when lets go off the ball sees the ball travel to the ground (accelerate) near to speed of light?
    I am sure i have made things clear by this statement. Ok language barrier is there.i am very poor in language.
     
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  5. eram Sciengineer Valued Senior Member

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    even an infinite proper acceleration would not cause the ball to reach c.
     
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  7. ash64449 Registered Senior Member

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    so black hole in this way is impossible right? Since blackhole can make ball travel at speed of light? Am i right?
     
  8. eram Sciengineer Valued Senior Member

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    no you're WRONG.

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  9. ash64449 Registered Senior Member

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    where?
     
  10. James R Just this guy, you know? Staff Member

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    Black holes don't have infinite gravitational acceleration. A black hole with the mass of the Sun would only have a gravitational acceleration equal to the Sun's (outside its event horizon).

    So, if the Earth was a black hole, then you'd only need to accelerate your object at 9.8 metres per second per second to create the same acceleration as the black-hole Earth's gravitational field at the distance of the Earth's current surface.

    No. You're wrong. See above.
     
  11. ash64449 Registered Senior Member

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    That means the reason by light is not able to escape from blackhole : space is that curved that it has ripe apart. So the reason why light is not able to escape from the blackhole is independent of acceleration produced by blackhole. Am i right?
     
    Last edited: Apr 7, 2013
  12. ash64449 Registered Senior Member

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    and the reason why an object turns into a blackhole is the answer that eram gave in his first post. When an object's radius become smaller than critical radius,it is able to break apart the space,turning it into blackhole..
     
  13. eram Sciengineer Valued Senior Member

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    Once you go within the Schwarzschild radius/event horizon (< R), all spacetime paths lead closer to the black hole's center.

    This applies to everything, including light. Basically, once you're within event horizon, you're permanently screwed

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    Note that the Schwarzschild radius is not equivalent to the event horizon in a rotating black hole, such as a Kerr black hole.
     
  14. ash64449 Registered Senior Member

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    795
    was my statement you quoted in this reply right?
     
  15. ash64449 Registered Senior Member

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    795
    thank you for the information!!
     
  16. eram Sciengineer Valued Senior Member

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    1,877
    too vague, idk
     
  17. ash64449 Registered Senior Member

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    795
    means?
     
  18. ash64449 Registered Senior Member

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    795
    what? Again a language barrier? C'mon,i have expressed in the way that everyone understands in this case!!
     
  19. ash64449 Registered Senior Member

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    yes.then why can't light escape if earth was turned into blackhole? Inother way, if an object wants to escape from the gravitational field,object's acceleration should be greater than earth blackhole. Well,light has its velocity higher than earthblackhole's escape velocity. Then we would visibly see it. Since blackholes cannot be seen,then how does this make sense?
     
  20. Prof.Layman totally internally reflected Registered Senior Member

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    Because if the Earth became a black hole then it wouldn't have the same escape velocity. It would take crushing the Earth to about the size of a marble. Then it would have more density, and a smaller radius. Then the gravitational force would increase, it would then have a higher escape velocity from the surface. It would then just be much smaller and have a smaller event horizon. So then you wouldn't be able to see the little black marble that would then be Earth.
     
  21. ash64449 Registered Senior Member

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    look at the comment of james r. He said acceleration due to gravity remains the same.so wouldn't escape velocity remain the same?
     
  22. Janus58 Valued Senior Member

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    Yes, look at JamesR's comment, he said, at the distance of the Earth's current surface. A black hole the same mass as the earth would have an event horizon with a radius of less than 1 cm. Thats how close to the center of the BH you would have to get for the escape velocity to equal the speed of light.

    The acceleration due to gravity at that distance would be ~5e17 time that at the present surface of the Earth.

    On the other hand, a super massive black hole of 1 billion solar masses would have an event horizon twenty times the radius of the Earth's orbit around the Sun and an acceleration due to gravity of ~6069 times that of the Earth's surface at the event horizon while still having an escape velocity of c.

    This is because there is not a direct relationship between escape velocity and surface gravity. (We even have an example of this in our own Solar system; The surface gravity of Uranus is less than that of the Earth's, yet its escape velocity is more.)
     
  23. ash64449 Registered Senior Member

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    Then why did JamesR said that ""to create a gravitational field equivalent to black hole's, an object needs to travel faster than the speed of light or it needs to travel at the speed of light."" is wrong?
     

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