Hi. 0+1=1 1+1=11 11+1=111 111+1=1111 1111+1=11111 11111+1=111111 111111+1=1111111 1111111+1=11111111 11111111+1=111111111 111111111-1=11111111 11111111-1=1111111 1111111-1=111111 111111-1=11111 11111-1=1111 1111-1=111 111-1=11 11-1=1 1-1=0 0×1=0 1×1=1 1×11=1+1=11 1×111=1+1+1=111 1×1111=1+1+1+1=1111 1×11111=1+1+1+1+1=11111 1×111111=1+1+1+1+1+1=111111 1×1111111=1+1+1+1+1+1+1=1111111 1×11111111=1+1+1+1+1+1+1+1=11111111 1×111111111=1+1+1+1+1+1+1+1+1=111111111 11×1=11 11×11=11+11=1111 11×111=11+11+11=111111 11×1111=11+11+11+11=11111111 etc. Now, if × = + THAT number of times... is ÷ ... Top×10 - How many bottoms?? (Answer÷10) e.g. 3÷9= 3+3+3+3+3+3+3+3+3+3= 30 - 9 = 21 (1) - 9 = (2) 12 - 9 = (3) 3 This is a recurring answer. So, ÷ answer by 10 3+3+3+3+3+3+3+3+3+3= 30 - 10 = 20 - 10 = 10 - 10 = 0 Answer=0.3'
River, Good question! What about a computer that programs itself?? Takes the first letter and puts it last. Takes the second letter and puts that last Takes the third letter ... etc. You can try this yourself. Name=Morpheus22 0<a<11 Name=Name+(Name(a)+10) Name=Morpheus22 Name=Morpheus22M Name=Morpheus22Mo Name=Morpheus22Mor Name=Morpheus22Morp Name=Morpheus22Morph Name=Morpheus22Morphe Name=Morpheus22Morpheu Name=Morpheus22Morpheus Name=Morpheus22Morpheus2 Name=Morpheus22Morpheus22
1×10=1,2,3,4,5,6,7,8,9,10 1÷10=1,0.9,0.8,0.7,0.6,0.5,0.4,0.3,0.2,0.1 10÷0.1= 1=10 2=20 3=30 4=50 5=50 6=60 7=70 8=80 9=90 10=100 I'd practice sitting.
P.s. Could someone have created artificial intelligence and appeared within the darkness? Could it happen again?? There are only 10 digital SYMBOLS: 0,1,2,3,4,5,6,7,8,9 0 is the 1st symbol and 9 the 10th. Only 10 SYMBOLS. 1_0 is to RE-USE 1 then 0. 1_1 is to reuse 1 then 1. 1_2 is to reuse 1 then 2. There are ONLY 4 OPERATORS:+,×,- and ÷. (I=i) (<=less than) Please read?? 0<a 0<b 0<c 0<d 0<e I(1)=((((a+b)×c)-d)÷e) I(2)=((((a+b)×c)÷d)-e) I(3)=((((a+b)-c)×d)÷e) I(4)=((((a+b)-c)÷d)×e) I(5)=((((a+b)÷c)×d)-e) I(6)=((((a+b)÷c)-d)×e) I(7)=((((a×b)+c)-d)÷e) I(8)=((((a×b)+c)÷d)-e) I(9)=((((a×b)-c)+d)÷e) I(10)=((((a×b)-c)÷d)+e) I(11)=((((a×b)÷c)+d)-e) I(12)=((((a×b)÷c)-d)+e) I(13)=((((a-b)+c)×d)÷e) I(14)=((((a-b)+c)÷d)×e) I(15)=((((a-b)×c)+d)÷e) I(16)=((((a-b)×c)÷d)+e) I(17)=((((a-b)÷c)+d)×e) I(18)=((((a-b)÷c)×d)+e) I(19)=((((a÷b)+c)×d)-e) I(20)=((((a÷b)+c)-d)×e) I(21)=((((a÷b)×c)+d)-e) I(22)=((((a÷b)×c)-d)+e) I(23)=((((a÷b)-c)+d)×e) I(24)=((((a÷b)-c)×d)+e) e<11 d<11 c<11 b<11 a<11 Would it EVER produce a.i.??