Anti-Gravity

Discussion in 'Physics & Math' started by Abhi, Mar 29, 2002.

  1. Abhi Registered Member

    Messages:
    22
    Anti-Gravity
    Mr. Abhijit Patil, C/o LIC of India, At/Po/Tq: Shahada City,
    Dist: Nandurbar,(MS), INDIA. Pin:425409. Email: xabhix@hotmail.com

    Abstract:

    This Article propose model to create anti-gravity.

    Introduction:

    Sir Issac Newton observed that if we pick up particle and drop it, it falls straight down on planet. If we throw this particle, instead of dropping straight down on planet, it travels in space for some distance then falls down on planet taking parabolic path. He further observed that if we throw this particle with certain(critical) velocity, the particle will keep travelling, rotating around planet and will never fall on planet! But, in this case, to overcome gravity of planet, particle must revolve around planet. This article aims to propose model to keep a body at fixed position above planet without falling on planet.

    Mathematical Model of Anti-Gravity:

    G = Gravitational constant,
    M = Mass of planet,
    m = Mass of particle,
    R = Radius of planet,
    v = Velocity of particle,

    As Newton explained beyond doubt through equations, kinetic energy(KE) of particle to escape from gravitational field of planet must be equal to gravitational potential energy of planet(U)

    KE = (1/2)m*v^2 and U = GMm/R
    As KE = U hence (1/2) m*v^2 = GMm/R
    so v^2 = 2*G*M / R
    i.e. v = (2GM/R)^(1/2)

    Now we must note here that we are dealing here with only KE of particle.

    If we take a circular ring and rotate it in vacuum with linear velocity v = (2GM/r)^(1/2), this ring will never fall on planet. It will keep rotating in vacuum forever. Because though the every particle of ring is rotating in definite space, still every particle in ring has linear velocity v and hence every particle has KE to counter gravitational potential energy(U) of planet. The ring will keep rotating in space where it is and gravity of planet will not act on ring. So planet will move in space but the ring will not.

    Orbital(critical) velocity of particle revolving around planet is given by v = (GM/R)^(1/2)

    So here also, as the particle has velocity v, we are dealing with KE of particle. Hence if we rotate the ring in vacuum with velocity v = (GM/R)^(1/2), it will keep rotating and never fall on planet, but still as the every particle in ring is under gravitational field of planet, ring will rotate with planet and at the same time move in space with planet. So the observer on planet will see the ring rotating at fixed position above the surface of planet forever. This ring will never fall on planet.

    Conclusion:

    We have Anti-Gravity.
     
  2. Google AdSense Guest Advertisement



    to hide all adverts.
  3. itchy Registered Senior Member

    Messages:
    47
    Congratulations on your Nobel prize for discovering anti-gravity...

    Seriously, you are lacking some fundamental understanding of physics. The rotational kinetic energy you are refering to is not the same as linear kinetic energy. The mass center of your rotating ring will be acted upon just like any other non rotating object, hence it will fall down to Earth.
     
  4. Google AdSense Guest Advertisement



    to hide all adverts.
  5. Adam §Þ@ç€ MØnk€¥ Registered Senior Member

    Messages:
    7,415
    Someone posted here the other day a link about NASA working with Podkletnov's gravity-shielding ideas. It seems possible, at least Podkletinov's way. Since NASA is spending so much money on it, there might be something in it.
     
  6. Google AdSense Guest Advertisement



    to hide all adverts.
  7. (Q) Encephaloid Martini Valued Senior Member

    Messages:
    20,855
    adam

    Hoaglandites website. Cranks and crackpots.

    http://www.enterprisemission.com/antigrav.html

    abhi

    Another theory? Now its anti-gravity.

    I see you still haven't got a grasp on the basics.

    Itchy's got you tagged on this theory.

    Good call Itchy.
     
  8. Abhi Registered Member

    Messages:
    22
    To understand rotational "kinetic energy" or linear "kinetic energy", we must understand what exactly is kinetic energy, to be correct, what exactly is "energy".

    Energy is nothing but density of spacelines associated with matter. This DSL is responsible for motion of matter. So gravity is nothing but DSL and KE is nothing but DSL. Gravity DSL is directed towards earth. If we associate exact amount of horizontal DSL with matter, it will counter gravity DSL and escape from planet.

    So KE is nothing but DSL.

    Abhi
     
  9. (Q) Encephaloid Martini Valued Senior Member

    Messages:
    20,855
    To understand rotational "kinetic energy" or linear "kinetic energy", we must understand what exactly is kinetic energy, to be correct, what exactly is "energy".

    Kinetic energy is the energy of motion. And since you need to start with basics....

    http://www.physicsclassroom.com/Class/energy/u5l1c.html

    Energy is nothing but density of spacelines associated with matter.

    Is this another one of your theories or can you provide some evidence, maybe a link?

    This DSL is responsible for motion of matter. So gravity is nothing but DSL and KE is nothing but DSL. Gravity DSL is directed towards earth. If we associate exact amount of horizontal DSL with matter, it will counter gravity DSL and escape from planet.

    Could we get another Nobel Prize for our budding scientist, please.

    So KE is nothing but DSL.

    Do we have a GUT?

    Please Register or Log in to view the hidden image!

     
  10. c'est moi all is energy and entropy Registered Senior Member

    Messages:
    583
    this Abhi is a funny character :bugeye:

    Please Register or Log in to view the hidden image!

     

Share This Page