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You originally asked, "how to prove that total kinetic energy after inelastic collision will be definitely less than the total kinetic energy before the inelastic collision. " What DEFINITION of "inelastic collision" are you using?? The only one I know is that kinetic energy is after the...

Can you suggest any experiments that would directly measure or otherwise confirm the existance of the "force" S? That's the key to any theory. In any case, since you call it a "force" are you suggesting that S can cause masses to change momentum? That would easily suggest experiments but...

360= 2*180= 2^2*90= 2^3*45= 2^4*3*15= 2^4*3^2*5. The only prime numbers between 1 and 10 are 2, 3, 5, and 7.

It's been seven pages and no one has answered that yet? "Space-time" is exactly what it says. Physics deals with "events". Things that happen at a specific place (space) at a specific time. Special Relativity shows that they cannot be separated- whether or not events occur at different...

"The whole point of this thread, is that the two sets cannot ever be equivalent." Yes, we UNDERSTAND that that is the whole point of this thread. That is why people have repeatedly told you it is not true. You wrote, as a premise, that "<font face="symbol"> "</font>t[not(M(t) =...

That phrase is part of the rites of the Masons.

If your table only goes up to 25, then use a normal approximation to the binomial distribution. The mean value, as kriminal99 pointed out, is .4*30= 12. The standard deviation is sqrt(.4*.6*30)= sqrt(7.2).

Mathematically? Sure, knock yourself out. Some problems in statistical mechanics deal in millions of dimensions (6 dimensions, x, y, z, vx, vy, vz for each particle.) But my impression was that the original post was asking about spacial dimension in string theory.

There is a very important difference between saying "we don't know for SURE that pi can be written as a ratio of integers" and saying "we DO know for SURE that pi CANNOT be written as a ratio of integers" and the latter is true. That's why we know for SURE that pi is not a rational number.

Okay, I thought you were objecting to defining "rational number" as a number that CAN be written as a fraction. You were only objecting to defining it as a number that IS written as a fraction or requiring that the numerator an denominator be known. That's fair. However, is not true...

If you think it can, go ahead and solve it! This, much like the classical multi-body gravtation problem, is a non-linear equation and non-linear differential equations are, generally, impossible to solve exactly.

"Actually we didn't do any of that stuff and dx was clearly indicated as an infintessimally small value." Then either it was a realy bad class or it was doing "non-standard" analysis (very strange for an introductory calculus class)- no introductory calculus text I have ever seen used...

If it's a lagrange point, then it's going to collect "dust"- that causes friction.

I hope what your professor actually said was that IF you define f(x)= (sin x)/x for x NOT 0, 1 for x= 0 THEN f is continuous. The function f(x)= (sin x)/x is not defined at x= 0 and has a "removable discontinuity" at x= 0.

Yes, relative to the ground, you were going faster than the bus! Of course, that's with the help of the bus. Since both the buses speed and your walking speed are far below speeds where relativity needs to be invoked, your speed, relative to the ground, was u+ v where u is your walking...

You aren't getting any responses because this doesn't really make a whole lot of sense! What do you mean by "how many choices"? Hitting at different angles? If you are thinking of the pocket as exactly fitting the ball, then there is only one (without rebounds). If the pocket is at all...

>“ Originally Posted by 1100f >You are talking about the mass of the atmosphere. ” >I expressed the math in terms of how much the mass of the atmosphere weighs in >newtons, which is a unit of weight. Read it again while you're thinking again. Absolutely! "weight" is a force, not...

Since you say "parliament", I presume you are thinking of England or one of European countries. It is a fundamental concept of the United States Constitution that there exist certain "rights" that cannot be abrogated even by the majority. Many of the laws passed by Franklin Roosevelt and...

The symbol you used here didn't show up on my reader. If is "intersection", then Z intersect R is just Z (which is a subset of R) and that is not open. However on the other problems you seem to be talking about "union". If this is "union", then Z union R is all of R and that is open.

Naror: actually its the other way around. As Janus58 said, the Greeks called a die "Kybos" which had nothing to do with multiplying. It is because of the multiplying that x^3 is called "the cube of x".