Displaying equations using Tex

Discussion in 'Physics & Math' started by Pete, Dec 20, 2006.

  1. ArafuraOpal Registered Member

    Messages:
    20
    \(\sum_{n=1}^{40} \left( \sum_{m=1}^n \left( \frac {a \sin \left( {3^{( m+(n^2-n)/2)}} \theta / b + l(\frac {2 \pi}{3}) \right) }{3^{(m+(n^2-n)/2)}} \right) \right) , l=-1,0,1 \)

    \(\sum_{n=1}^8 \left( \sum_{m=1}^n \left( \frac {a \left( \sin \left( {3^{( m+(n^2-n)/2)}} \theta / b + k(\frac { \pi}{3} ) + \cos \left( {3^{( m+(n^2-n)/2)}} \theta / b + k(\frac { \pi}{3} ) \right) \right) }{2 \times 3^{(m+(n^2-n)/2)}} \right) \right) , k=-1,1\)
     
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  3. ArafuraOpal Registered Member

    Messages:
    20
    \( \sum_{n=1}^{40} \left( \sum_{m=1}^n \left( \frac {a \sin \left( {3^{( m+(n^2-n)/2)}} \theta / b + l(\frac {2 \pi}{3}) \right) }{3^{(m+(n^2-n)/2)}} \right) \right) , \ l=-1,0,1 \)

    \( \sum_{n=1}^8 \left( \sum_{m=1}^n \left( \frac {a \left( \sin \left( {3^{( m+(n^2-n)/2)}} \theta / b + k(\frac { \pi}{3} ) + \cos \left( {3^{( m+(n^2-n)/2)}} \theta / b + k(\frac { \pi}{3} ) \right) \right) }{2 \times 3^{(m+(n^2-n)/2)}} \right) \right) , \ k=-1,1\)
     
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  5. ArafuraOpal Registered Member

    Messages:
    20
    \(\displaystyle \sum_{n=1}^8 \left( \sum_{m=1}^n \left( \frac {a \left( \sin \left( {3^{( m+(n^2-n)/2)}} \theta / b + k \times (\frac {\pi}{3} ) \right) + \cos \left( {3^{( m+(n^2-n)/2)}} \theta / b + k \times (\frac { \pi}{3} ) \right) \right) }{2 \times 3^{(m+(n^2-n)/2)}} \right) \right) , \ k=-1,1\)
     
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  7. icarus2 Registered Senior Member

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    122
    \( {U_{es - shell}} = \frac{1}{2}(\frac{1}{{4\pi {\varepsilon _0}}}\frac{{{Q^2}}}{{{R_{es}}}}) \)
     
    Last edited: Apr 29, 2018
  8. Beer w/Straw Transcendental Ignorance! Valued Senior Member

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    5,862
  9. James R Just this guy, you know? Staff Member

    Messages:
    35,615
    fgfggh indeed.

    Please Register or Log in to view the hidden image!

     
  10. Confused2 Registered Senior Member

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    607
    Last edited: Jun 11, 2020
  11. Confused2 Registered Senior Member

    Messages:
    607
    \(s^{2}={v'_{x}}^{2}t'+ {v'_{y}}^{2}t' -c^{2}t'^{2}\)
     
    Last edited: Jun 11, 2020
  12. Amadeusboy Registered Member

    Messages:
    22
    If anyone can help it would be appreciated. I have been trying to display an equation with Tex with no luck. I have refreshed the page and still get nothing. Do I have to create the thread to actually see if the equation is correctly expressed?
     
  13. Neddy Bate Valued Senior Member

    Messages:
    2,119
    In my experience, the Tex equations do not display correctly in the "preview" pane, but they do display correctly after they have been posted to a thread. You can use this thread to check your Tex equations for errors, before posting or creating a whole new thread. Sorry, but this forum software still has some bugs in it.
     
  14. Amadeusboy Registered Member

    Messages:
    22
    \( \Large \frac{1}{1-\frac{v^2}{c^2}} \)

    Thanks for your help Neddy Bate. I see that you have to post to see the equation displayed. The preview does not display the equation.
     
    Last edited: Jun 28, 2020
  15. Confused2 Registered Senior Member

    Messages:
    607
  16. foghorn Registered Senior Member

    Messages:
    583
    \(\sqrt{ab}\)

    \(c_a^b\sqrt[n]{ab}\)

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    Last edited: Jun 28, 2020
  17. foghorn Registered Senior Member

    Messages:
    583
  18. foghorn Registered Senior Member

    Messages:
    583
    \(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
     
  19. ralfcis Registered Senior Member

    Messages:
    279
    How do I make "\( h_2^\)" appear as plain old text?
     
  20. ralfcis Registered Senior Member

    Messages:
    279
    tex] h_2^0[/tex]

    I've read this thread, I've googled it, this is the closest I've gotten.Just remove the 1st sq bracket
     
    Last edited: Jan 30, 2021
  21. ralfcis Registered Senior Member

    Messages:
    279
    This is my equation sheet to cut and paste equations:
    I need to ferret out embedded script here

    \( \)

    \( c^2 = v^2 +v_t^2\)
    \(Y = \frac{c}{ \sqrt{(c^2-v^2)} } \)

    \(v_t= c/Y \)
    \( v = c/Y_t\)

    \(w =(v+ u) / (1 + vu/c^2)\)

    \(c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2\)

    \((ct')^2 = (ct)^2 - x^2 \)

    \((ct)^2= (ct')^2+ x^2 \)




    \(v/(c-v) = 2cv_h / (c - v_h)^2\)

    \(Y = 2Y_h^2 - 1 = (c^2 + v_h^2)/(c^2 - v_h^2) = c/v_t = (1/(1-v_h/v)) -1 = 2c^2v_hv/(c^2 - v_h^2) = 2Y_h^2 v_h /v \)

    \(v_h=Yv/(Y+1) \)

    \((Yv)^2 = v^2/(1-v^2)\)

    \(v= c sqrt(Y^2-1)/Y\)



    \(t'=x(v_h +c)/c \)

    \(v' = Yv\)
    \(t = Yt'\)
    \(x'=Yx\)

    \(Yv =x/t'\)

    \(Yu/Yw=DSR_v\)

    \( t'(1-Y) \)
    \(t'=x/Yv\)
    \(vx/c^2\)

    \(tpad=t′−x/Yv\)

    \(t'=sqrt(t^2- x^2)\)

    \(t' =xDSR_o/Yv\)



    \(wt= c / Yw = c / (YvYu(1 + vu/c^2)) \)

    \(Y_ww = (v+u)YuYv \)



    \( cDSR = sqrt((c-v)/(c+v)) \)

    \(DSR_v= Yu/Yw\)

    \(Y(c-v) = c/DSR\)

    \(DSR_w= DSR_v* DSR_u \)
    \(DSR_w^2= (c-w)/(c+w) \)

    \(w = c(1-DSR_v^2 DSR_u^2 )/(1+DSR_v^2 DSR_u^2 )\)

    \(DSR = Y(1-v/c)\)

    \(t' = X(c+v_h)/c \)

    \( t'(DSR - 1)\)

    \(t' = X(-2v_h)/(c+v_h) \)

    \(A = (v+u)\)

    \(B= (1+vu/c2)\)

    \(sqrt(c^2B^2-A^2) = c/YvYu =v_tu_t\)



    v Y vh" role="presentation" style="display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">vhvhvt" role="presentation" style="display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">vtvtv_h_t" role="presentation" style="display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">v_h_tv_h_t DSR t'

    1 1 1 0 0 0

    3280/3281 3281/81 40/41 81/3281 1/81 81

    40/41 41/9 4/5 9/41 4/36 9

    255/257 65/16 15/17 16/65 1/8 8

    24/25 25/7 3/4 7/25 1/7 7

    35/37 37/12 5/7 12/37 6/36 6

    12/13 13/5 2/3 5/13 1/5 5

    77/85 85/36 77/121 36/85 8/36 9/2

    15/17 17/8 3/5 8/17 9/36 4

    4/5 5/3 1/2 3/5 12/36 3

    3/5 5/4 1/3 4/5 18/36 2

    1/2 1.155 .268 .866 .577 1.73

    8/17 17/15 1/4 15/17 3/5 5/3

    5/13 13/12 1/5 12/13 24/36 3/2

    1/3 1.06 .17 .943 .707 1.41

    12/37 37/35 1/6 35/37 5/7 7/5

    7/25 1/7 24/25 27/36 4/3

    16/65 1/8 255/257 15/17 17/15

    9/41 1/9 40/41 4/5

    0 0 1 1

    21523360/21523361 21523360/21529922 6561/21523361 1/6561
     
    Last edited: Jan 30, 2021
  22. ralfcis Registered Senior Member

    Messages:
    279
    \( \)

    \( c^2 = v^2 +v_t^2\)
    \(Y = \frac{c}{ \sqrt{(c^2-v^2)} } \)

    \(v_t= c/Y \)
    \( v = c/Y_t\)

    \(w =(v+ u) / (1 + vu/c^2)\)

    \(c^2= ((v+u)^2+ v_t^2u_t^2) / ( 1 + vu/c^2)^2\)

    \((ct')^2 = (ct)^2 - x^2 \)

    \((ct)^2= (ct')^2+ x^2 \)

    \([tex]v = v_h(v_t/c +1)\) [/tex]
    \(v_t = v_h_t(v/c +1) \)
    \( [tex]v = 2c^2v_h / (c^2 + v_h^2) \)[/tex]
    \(v_t = 2c^2v_h_t / (c^2 + v_h_t^2)\)

    \( v_h = c(c-v_h_t ) / (c+v_h_t )\)
    \( v_h_t = c(c-v_h ) / (c+v_h )\)

    \(v/(c-v) = 2cv_h / (c - v_h)^2\)

    \(Y = 2Y_h^2 - 1 = (c^2 + v_h^2)/(c^2 - v_h^2) = c/v_t = (1/(1-v_h/v)) -1 = 2c^2v_hv/(c^2 - v_h^2) = 2Y_h^2 v_h /v \)

    \(v_h=Yv/(Y+1) \)

    \((Yv)^2 = v^2/(1-v^2)\)

    \(v= c sqrt(Y^2-1)/Y\)

    \(v_t = c/Y = DSR(c+v) = v_h_t(1 +v/c)\)

    \(t'=x(v_h +c)/c \)

    \(v' = Yv\)
    \(t = Yt'\)
    \(x'=Yx\)

    \(Yv =x/t'\)

    \(Yu/Yw=DSR_v\)

    \( t'(1-Y) \)
    \(t'=x/Yv\)
    \(vx/c^2\)

    \(tpad=t′−x/Yv\)

    \(t'=sqrt(t^2- x^2)\)

    \(t' =xDSR_o/Yv\)

    \(t_p_s= xv_p_s = xYv/(1+Y) \)

    \(wt= c / Yw = c / (YvYu(1 + vu/c^2)) \)

    \(Y_ww = (v+u)YuYv \)

    \(v_h_t=cDSR \)

    \( cDSR = sqrt((c-v)/(c+v)) \)

    \(DSR_v= Yu/Yw\)

    \(Y(c-v) = c/DSR\)

    \(DSR_w= DSR_v* DSR_u \)
    \(DSR_w^2= (c-w)/(c+w) \)

    \(w = c(1-DSR_v^2 DSR_u^2 )/(1+DSR_v^2 DSR_u^2 )\)

    \(DSR = Y(1-v/c)\)

    \(t' = X(c+v_h)/c \)

    \( t'(DSR - 1)\)

    \(t' = X(-2v_h)/(c+v_h) \)

    \(A = (v+u)\)

    \(B= (1+vu/c2)\)

    \(sqrt(c^2B^2-A^2) = c/YvYu =v_tu_t\)
     
    Last edited: Jan 30, 2021
  23. ralfcis Registered Senior Member

    Messages:
    279
    \(v=vh(vt/c+1)" role="presentation" style="display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">tex]v=vh(vt/c+1)[tex]v=vh(vt/c+1) \)
     

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