# Japanese solution?

Discussion in 'General Science & Technology' started by universaldistress, Mar 15, 2011.

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I can't be certain exactly what you are asking so I'll just make a couple of factual statements. The electrons of ANY atom exist in specific energy levels unless disturbed. Note carefully that these are specific - FIXED - energy levels. That means there are no fractional levels possible.

Rather than guess at what you are after - or worse yet, allow you to depend on Rabon's NONSENSE - I'll give you a highly informative link to an excellent article on electron energy levels. I suggest you not just read but actually STUDY this information. I'm a little concerned that the majority of it is well over your head but at least it will provide you with truthful answers (again as opposed to Rabon's garbage) and you will learn some interesting things.

3. ### DwayneD.L.RabonRegistered Senior Member

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999
Electrons at different energy levels results in different bandwidths of photons. Atoms lose electrons when radiation like gamma and beta rays are released or transmitted, photons like X-rays are also released. Radioactive atoms have energy levels that have a constant variation as they are radioactive and so the atoms is trying to find a balance of energy with the electrons and nucleous.

Ok here is the State of energy transmission in Radiation at the Nuclear Facility, given the temipture as last advertised 100 degrees Celsius.
The Director of TEMPCO Electric recently released a statement that it was difficult to determine what was going on in the reactor.
This amount of 831,866 pounds of material, at 100 degrees celsius has 0.471889238 pounds of material that transmits radiation per. second. Where 0.004403134 pounds transmits Gamma radiation and 0.432565168 pounds that transmits Beta Radiation(that is 2.1485 x 10^25 gamma rays and 2.3634 x 10^26 Beta rays).
The Desired tempiture would be around 11 degrees Celsius or 1.997227986 grams transmiting gamma per sec. and 21.9695 grams transmiting Beta rays per second..

If you have the tempiture you can use the above figures to tell the state of radiation energy transmission.

As for radioactive elements that have been dumped into the sea at the Nuclear Facility the radioactive cesium will have a tendency to remain as particles in water and settleing untill May 10th as a result of a increase in the Background Electron Chemistry.

DwayneD.L.Rabon

Last edited: Apr 8, 2011

5. ### KumarRegistered Senior Member

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1,990
Ok thanks, I shall read & study.

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10,296
That's very good, Kumar.

Now you'll be seeing some solid science instead of stuff just made-up on the fly.

It really IS some interesting information. It's also the beginning of the explanation of other things as well, one of them being why the speed of light appears to slow down when light travels through a different medium. That was quite a puzzle until it was figured out.

We now know that the speed of light does not change at all, rather that the photons are absorbed by electrons in the cloud around the nucleus - causing them to jump to a higher energy state - and when they fall back to the rest state a photon is re-emitted. Those two steps take a bit of time and the result is a delay in the transmission, not a reduction of speed of the photons themselves.

And that's the interesting kind of REAL science facts you can learn by going to the right sources.

8. ### DwayneD.L.RabonRegistered Senior Member

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999
Well
Today in Japan The Paramagnetic Phase of Uranium will begin, meaning the the preformance of paramagnetic behavior will start to become stronger in uranium and the Nuclear Facility, The Paramagnetic Phase of Uranium comes to a end on the 12th of April. During the Paramagnetic phase dust particles and atoms will behave like a magnet. There are likly to be spikes of radiation emmissions, if the tempiture of the Uranium material at the Nuclear Facility is low, meaning the Tempiture of the Spent Fuel Pool and Reactor. If the tempiture is high then a failure of the paramagnteic preformance will exist as with most magnetics.
The Paramagnetic phase also starts when the isotope formation phase is the longest for this month. The Isotope Phase combined with the increase in Background Electron Chemistry will bring the radioactive material to stablity, Producing less rampant volatile particles and radiations as the isotopes find greater stability. This appears to be the longest Isotope phase and closest in line with high Background Electron Chemistry which reaches its maxium about May 10th when Background Electron Chemistry will begin to start decreaseing.

For the next few days isotope phase will last about 18 hours.

Uranium at the nuclear facility just finished the Zirconium phase which involved the release of Volatile material from the central mass of materials reducing the number or reactions untill current.

DwayneD.L.Rabon

9. ### DwayneD.L.RabonRegistered Senior Member

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999
Well,
In the enviromental imapct of operating a Nuclear Facility, at a radius of 57 miles from the facility there is one intereactive distrubance every 4,870,149 square Angstroms at a tempiture of 100 degrees Celsius. At a tempiture of 11 degrees Celsius there is one distrubance per 43,494,977 square angstroms area. per second.
A ripple is started for each distrubance, this creates a effect like rain drops falling on a pool of water. within the area background across 10,574 square miles.

DwayneD.L.Rabon

Last edited: Apr 9, 2011
10. ### KumarRegistered Senior Member

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1,990
Ok thanks. I shall visit bit later.

11. ### KumarRegistered Senior Member

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1,990
Ok thanks. I shall visit bit later.

Messages:
999
dwayne

13. ### DwayneD.L.RabonRegistered Senior Member

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999
Well,
Today is April 17th,2011 and the current Phase for Uranium at the nuclear facility in Japan is Vanadium Phase . Meaning that the release of volatile material is taking place from the main body of mass in the spent fuel pool and the reactor.
Other phases exist such as Isotope Phase and Tin Phase, Isotope phase sets the circumstances of vanadium phase as isotopes release volatile particles in to the bulk of uranium mass, where vanadium phase results in the release from the main body of mass. Tin Phase shows a predominace of uranium to melt, representing the elastic property of uranium, or ductility of uranium, other phases simular to tin phase exist but last for short periods of time being about 15 minutes and so are not worth much mention in the scale of a day of opreation time of a nuclear reactor.

For the next few days the vanadium phase will last for about 6 hours,tin phase also about 6 hours and Isotope Phase for 12 hours. Showing three prime phases for a day.

DwayneD.L.Rabon

DwayneD.L.Rabon

Last edited: Apr 18, 2011
14. ### DwayneD.L.RabonRegistered Senior Member

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Here is the radiation status of the reactors buildings at fukushima daichi nuclear facility. under the condition that each building contains approximatly 831,866 pounds of radioactive material

Building Unit 1 and 2
Current Tempiture 30 degrees celsius
Gamma release 0.0117972 pounds per second(5.35113261grams or 6.445593023 x 10^24 gamma particles)
Beta release 0.12976953 pounds per second(58.86247482grams or 7.090337211 x 10^25 particles)
Static background in cycle 24,751,776.6 Coulumbs
Undetectable instrument measure 5,999.9 Coulumbs
General release, radation emmission per atom. every 7.1252 minutes

Building Unit 3
Current Tempiture 20 degrees celsius
Gamma release 0.0078648 pounds per second(3.56742174grams or 4.297286826 x 10^24 gamma particles)
Beta release 0.08651302 pounds per second(39.24164958grams or 4.72689147 x 10^25 particles)
Static background in cycle 16,501,184Coulumbs
Undetectable instrument measure 3,999.9 Coulmbs
General release, radation emmission per atom. every 10.6879 minutes

Building Unit 4
Current Tempiture 90 degrees celsius
Gamma release 0.0353916 pounds per second(16.05339783grams or 1.933779072 x 10^25 gamma particles)
Beta release 0.38930859 pounds per second(176.5874245grams or 2.127101163 x 10^26 particles)
Static background in cycle 742,553,302 Coulumbs
Undetectable instrument measure 17,999.9 Coulmbs
General release, radation emmission per atom. every 2.375090982 minutes

DwayneD.L.Rabon

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10,296
It's refreshing (and relieving) to see that no one is paying any attention to our in-house "genius"/scientific idiot.

Perhaps another week or so of that and he will go back to playing with his imaginary toys and numbers in his own little padded room...

16. ### DwayneD.L.RabonRegistered Senior Member

Messages:
999
Well, here is a Issue regarding enviromental imapct. radioactive material has been a drift in air effecting a large area that will be once again lived on by humans who depend on the Soil conditions.
The March 14th explosion increased the area effected where due to the March 14th Hyrdogen expolsion the maxium settling time and area are 205.89 days over 5,127,020.43 sq. miles. The average settling time of material releases on all of the remaining 39 days is 9.1 days to 26 days, with a particle settleing area ranging from 226,818.07 sq. miles to 647,434.38 sq. miles.(particles that have exstended elevations above 2,516 ft can drift for excessive periods of time).

In Treating the effected Area: Acclerating the growth of plant life in the evacuation zone to allow the plant life to out grow abnormalities caused by radioactivity and allowing plant life to shed larger foilage to produce a greater biomass(increaseing the carbon background in soil) to radioactive particle ratio. Decrease the cumlative density in soil per sq. mile. making the area easier to collect and clear as well more livable and workable insulating against radioactive particles. To avoid a gain into the food chain the entire area would have to be land cleared by machine, and not fire or burning foilage.

In September, fall season will cause a great deal of leaf fall, changing the enviroment imapct.

The Area of the nuclear Facility being about 5,103.5 square mile on land would require 4,268,322,432 tons fertilizer(plant growth formula) at 60 pounds fertilizer per sq.ft. or at 71,138,707.2 tons fertilizer distribute 1 pound per square foot area of the effected area , and 156,834 tons at 1 gram fertilizer per square foot.

The best supply of nuterints to planet life in the area is 0.03 lbs for every pound of terrain plant life per day. A estimate of 6 pound per square foot would require 12,804,967.3 tons food resource per day for plant life in the area. For one Season or 90 days this would require 1,152,447,057 tons food resource for plant life

The best elevation for distribution of plant growth formula is 221 ft. from land contour elevation, when distribution is a liquid delivered by air spraying from a plane (meaning also 221 ft. from the tree tops).

DwyaneD.L.Rabon

Last edited: Apr 22, 2011
17. ### DywyddyrPenguinaciously duckalicious.Valued Senior Member

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I think his best-ever post was #209.
Short, succint and mostly accurate (except for the capitalisation and punctuation error).

Messages:
10,296
Indeed! And, as you pointed out, he couldn't even get THAT one right!!

19. ### DwayneD.L.RabonRegistered Senior Member

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999
Well,
The release of material from Japans Nuclear facility appears to be quite large, defining that intensive enviromental clean up and maintence will have to be undertaken.
The release from each reactor building amounts to approximatly 18.85 tons of radioactive material. 6.814 tons of Uranium residue with varaible ranges,4.969 tons of Cesium,4.969 tons Iodine vapors, 2.1036 tons other radioactive material. This accounts for about 21 fuel rods in evaporation, or 67.24 pounds of material released from each fuel rod during shrinkage and fuel rod deterioration of the estimated 483 fuel rods in each building unit.

The total for the Nuclear Facility is 75.429 tons radioactive material released to the enviroment.

DwayneD.L.Rabon

20. ### universaldistressExtravagantly Introverted ...Valued Senior Member

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That is very interesting Dwayne. Could you post your workings as I am working on the same equations, and I am figuring less has been released?

21. ### DwayneD.L.RabonRegistered Senior Member

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Well, Ok
I can show several meathods that show several figures nearly the same as estimates. (give me a day to respond back, on limited time)

In dealing with the release of matieral Cesium ia averaged as the majority of problematic material released, even though material of simualr weight range have been produced. wherein the estimate is 4.9 tons cesium. The exstended time of cesium and its decay products will remain in the enviroment having reoccurring tranist in the enviroment for about 80 years. Currently untill May 10th cesium will show the tendancy to remain as a particlulate making fewer chemical reactions or bonds, this will lead to cesium forming larger molecules or particles in the enviroment (where pooling in locations), after May 10th the rate of cesium to make chemical bonds will begin to increase, these chemical bond will be limited in time duration of the new chemical in formation as cesium being radioactive distrubs the bonding and begins a new course of tranist. Over the enviromental terrain and climate pattern of north Japan this disturbance occurs in general radiation emmission from cesium atoms in the feild ranging from 10.6 minutes to 214 minutes, causing the breaking and reformation of chmeical bonds,(generating background energy) every 38.2 days cesium will have very strong radiation emmission the will cause projection of the cesium atom over some distance or causing it to become a high velocity gas.
The greatest increase in general radiation emmision or intensity occurs at about 4 AM. Japan time. a range of two hours before and two hours after 4 am should be restricted time, no work in the feild during these times.

Number of deposit of radioactive materail exist to be approximatly 1.500622706 x 10^20 deposits at elevations below 629 ft.the majority of dispersion appearing to be within 30 miles radius, for each group of cesium material released from one reactor over 38 days. Where each deposit on average contains 136,054,474 cesium atom of which 42 atoms release strong radations per second, 210,000 to 10,000 producing general radation per second , and ever 24 seconds a decay releaseing beta and its by product.

DwayneD.L.Rabon

22. ### DwayneD.L.RabonRegistered Senior Member

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999
Well,
It definitly looks like there will be plently of records to sort out the diffrences in the finalilty of arguments or descrepency.

I would recommend determining the amount of radiation the material emits, and for eV exspressed in emmission count a chemical bond or atomic distrubance, for example a x-ray of 0.05 to 30 KeV would distrub as much as 30,000 atoms, a beta emmission would disturb 200 to 15,000 atoms and gamma 20,000 to 1,500,000 atoms. The disturabnce becomes deterioration as it breaks bonds on the surface of the material causeing clevage or surface fragmentation. you could use Ionzation potentials to determine the seperation of indivdual atoms from the main body of material, however some areas of the material will fragment in larger particles.

In my determination the rate of emmission was 0.424700314 pounds of material radiating radiations per second,oscillating within 831,866 tons of radioactive waste producing random locations of deterioration at 90 degrees Celsius this produced a disturbance of 55.6 tons, in which case 55.6 tons would be the maxium range of decompostion( where the breaking and reformation of chemical bonds forms a vibration of 55.6 tons).
In the 38 days I account for the tempiture has fallen to 22 degrees Celsius showing a decrease in distrubance where at 22 degrees the disturbance rate is 13.5 tons of material.

When looking at the effects by the expended energy the amount of water evaporated was 6,487.2 tons, the capacity of the spent fuel chamber was estimated to be 3,243.6 tons in about 9 days the spent feul pool evaporated 2,432.7 tons of water covering the fuel rods. 811 tons became reactive with the fuel rods producing oxidative volume in addition to incoming oxygen at level of exsposer. 2,432.7 tons in evaporation is suffcient to energy to liquidate 214 tons of Uranium and boil 58.8 tons Uranium and evaporate 4.43781506 tons of Uranium. Over 38 days 6,487 tons of water was evaporated enough to evaporate 11.8 tons of uranium.

As the chemical bond under vibrational disturbance is 55.26 tons and the energy transmitted is suffcient to boil 58.8 tons of Uranium a structual deformation of 58 tons will exist within the stored fuel rods with additional deforamtion caused by the presence of oxygen resulting in deformation of 13.94% (67 fuel rods out of 483). Of the 67 fuel rods damaged 5.1 to 13.7 fuel rods have evaporated 4.437 to 11.8 tons material. the byproduct waste material such as Cesium and Iodine could be estimated to be 20% to 4% of the orginal uranium content, accounting for about 2.32 to 11.6 tons in exsposer to evaporation.

just about 50% of the Radioactive material released from the Nuclear facilty will fall within 24 to 30 miles of the facility the remaining 50% of material has a range of 144 miles radius, with secondary Particle drift at a range of 268 miles radius over 9.1 days to 453.5 miles radius over 26 days. the volume of air containing material is approximatly 13,898 cubic miles in the region of Japan, The range of 144 miles radius can only contain such a volume if the area over the nearby sea is inculded and exstended to a elevation of 2,516 ft.

The coast line within the 9.1 day drift area would also have to be exstended from the 630 ft elevation to 2,516 ft elevation to absorb about half of the volume in which particles have at some point gained. The 9.1 area could contain the volume below 630 ft elevation if the area over the near by sea within the radius is inculded.

DwayneD.L.Rabon

Last edited: May 2, 2011
23. ### DwayneD.L.RabonRegistered Senior Member

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999
Well,
The release of radioactive material is most concentrated within the 30 mile radius of the Nuclear Facility, This area is about 2,827.432 square miles. radiaoactive material has fallen in this area in groups or plumes and it seems that these subgroup areas within the 30 mile radius would be sprayed with the poly-resin suggested by TEMPCO to hold radioactive material in place and prevent spreading.
To spray a poly resin over a area with a 5.7 miles radius having a area of 102.07 square miles and within the 30 miles it would require 24,898,631.73 gallons of resin to effectively cover such a area. The Leaf Surface Area is 5,691,115,823 square feet at full growth for the area, the ground surface area is 4,268,336,867 sq. ft. for a total of 9,959,452,690 sq.ft. that can be sprayed. 2,845,557,911 sq.ft of area will avoid the spray due to defelection, this also will be the Surafce Area containing or trapping cesium and other vapors rising in the area during summer time.

The area will produce about 1.707334394 x10^10 pounds of vegitation, and by fall in September it will shead in leaf fall resulting in 1,021,601.728 tons of carbon that will cover and react with the radioactive material released from the Nuclear plant.

At low estimate of 2.153284 tons of radioactive by product has been released, 50% of that material has fallen within 30 miles resulting in about 7.50316853 x 10^19 vapor plumes of cesium, and 6.587095495 x 10^15 vapor plumes of Iodine, other material exist to be released and are assimulated in to the above vapor plumes or clouds.
Cesium plumes overlap falling in a area with a 5.7 mile radius resulting in surface deposits of about 792,570,795 cesium atoms forming a molecule about 9.375 micrometers in diameter,once setting down the molecule begins to divide and seperate untill it froms daughter molecules of about 1.12 nanometers (95,311 cesium atoms), it is this nanomolecule that exist within the depth of soil.
Iodine plumes falling in the same area result in surface deposits of about 9.816096728 x 10^12 iodine atoms forming a spanning moluecule of about 11.5 centimeters or gas group. if the iodine can condense and sperate it will try to form a daughter molecule or cluster of about 55.4 micrometers (containing about 1,180451,681 atoms).

In smaller sub-group deposits of half the radius,the above figures can be multiplied by 4. For each onehalf of the radius multiply by 4 to give the result and particle size for that area as well as leaf area to calculate the rainwater transit, for example to find the figures for a area with a radius of 2.85 miles or a diameter of 5.7 miles multiple by 4 (the leaf surafce area figure is adjusted for the area near the nuclear plant accounting for crop leaf and tree leaf so can not be magnified to areas with greater diameter than 60 miles).

In a even distribution over the radius area of 30 miles or 2,827.432 square miles there area 1 cesium atom per 127 area atoms,and 1 Iodine atom for each 117 non-radioactive atoms in the area.

DwayneD.L.Rabon

Last edited: May 3, 2011