Math question

I DON'T UNDERSTAND!!! :bawl: I've confused myself.


1) First, x = 0.99999.
2) 10 times 0.99999= 9.99999, so this means 10x equals 9.99999. Right?
3) Now take away x from 10x to get 9x. (9.9999 - 0.99999 = 9)
4) So 9x equals 9, which means x equals 1.
5) So 0.99999 = 1, right???

 

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1) correct
2) 10 * 0.99999 = 9.99999

since in 1 you stated that X=0.99999 why would it change?

times also has a symbol for it x or *...dont confuse it with X as a variable....
3) 10 * (X) = 10 * (0.99999) = 9.99999
X= 0.99999
the value of 10X - value of X = 9.99999-0.99999= 9

Correct

4) 9*X does not equal 9, you are confusing multiplication symbol with X value
5) 0.99999=0.99999

 

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No, it'd be 9.99990.

 

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Surely Orleander is talking about 0.99999..., not 0.99999. This topic (0.999...=1) has been discussed to death here, here, and elsewhere.

Please, somebody lock this thread!

 

oh yes please. sorry. I'll go read those ones and maybe I'll get it. sorry again!

 

No, Orleander, it has been perfectly answered in post #3.

I mean, its not related to infinity threads which referred by post #4

10*0.99999 =/= 9.99999

10*0.99999 = 9.99990

 

This is the complete answer:

1). x = 0.99999
2). 10x = 10*099999 = 9.99990
3). 10x - x = 9x
-----9.99990 - 0.99999 = 8.99991
4). 9x = 9*0.99999 = 8.99991
5). So 8.99991 = 8.99991

 

Probably means 9.99999.....infinite 9s........

9.99999....recurring = 10

 

If he meant \( 0.999... \) then, yes, it's equal to \(1\).

 

If this has been brought up before somewhere else, I'll be happy to hunt.

I often wonder:

If .99999.... = 1 (which I know is true)
Then does

1.111111....... = 1.2?

 

No, but \(1.19999...\) does.

 

lol

 

Pete... James R... Stryder... someone.. close this thread NOW

No.... what is your logic in that?!

 

There is no way 0.9999....=1. Never. Not a chance.

Now this thread can be closed.

 

absane is back...

 

Whenever a thread about "0.999... = 1" is created, I get a telepathic call to come in and end all the madness. When this "issue" is "debated" by nonmathmaticians... nothing good can come out of it.

 

Polygon is never a circle....
......just as 0.99999 is never a 1
.....just as love is never forever....just as autumn never comes after spring' eternal tears

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Who said anything about a polygon being a circle? By definition, a circle can't be a polygon. Just as.. BY DEFINITION...

0.9 != 1
0.99 != 1
0.999 ! = 1

BUT... just as with the limiting process one can apply to a polygon... 0.999... = 1.

If you haven't taken a course in analysis or even calculus, don't bother "debating" whether 0.999... = 1 or not.

 

you are talking about limits...and I know.

if 0.999 were to continue the numerals until infinity or end it would never equal 1.

 

\(\{0.9, 0.99, 0.999, ...\} \cap \{1\} = \emptyset\).

But the least upperbound of the set \(\{0.9, 0.99, 0.999, ...\}\) is 1.