1) 4 friends, 2 females and 2 males, are playing contract bridge. Partners are randomly assigned for each game. What is the probability that the 2 females will be partners for the first game? [By listing out everything, I got a probability of 1/3. By using the probability formula, Probability is n(2 females)/n(Universal Set)=2C2/4C2=1/6. And I got a different answer. How can I solve this problem?] Thanks for helping! Please Register or Log in to view the hidden image!