Space time is reality Pseudo

Discussion in 'Pseudoscience' started by chinglu, Oct 19, 2013.

  1. chinglu Valued Senior Member

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    1,637
    OK, you retreat.
     
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  3. paddoboy Valued Senior Member

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    No, not at all.....
    Get it peer reviewed...take it to the masses...

    Why you do not????
    Because you will reveal yourself as an Idiot to the world instead of just in a pseudoscience forum.

    tell you what chinglu...You will certainly get a prize for the champion question avoider....You have that in the bag!!!
     
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  5. chinglu Valued Senior Member

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    This is not a peer review forum.
    So, obviously you cannot refute the argument I presented.

    Move along.
     
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  7. paddoboy Valued Senior Member

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    It's been refuted many times...The answers though label you as a fool.

    Of course this isn't peer review...That's what I've been saying here and in the other thread......So obviously any one with anything worthwhile would get it peer reviewed at a reputable outlet....Get it???
     
  8. chinglu Valued Senior Member

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    1,637
    Let's see the refutation.
     
  9. paddoboy Valued Senior Member

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    It's been posted many times, and you ignore it....Let's see the peer review?
     
  10. paddoboy Valued Senior Member

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    Minkowski Metric
    The Minkowski metric, also called the Minkowski tensor or pseudo-Riemannian metric, is a tensor eta_(alphabeta) whose elements are defined by the matrix

    (eta)_(alphabeta)=[-1 0 0 0; 0 1 0 0; 0 0 1 0; 0 0 0 1],
    (1)
    where the convention c=1 is used, and the indices alpha,beta run over 0, 1, 2, and 3, with x^0=t the time coordinate and (x^1,x^2,x^3) the space coordinates.

    The Euclidean metric

    (g)_(alphabeta)=[1 0 0; 0 1 0; 0 0 1],
    (2)
    gives the line element

    ds^2 = g_(alphabeta)dx^alphadx^beta
    (3)
    = (dx^1)^2+(dx^2)^2+(dx^3)^2,
    (4)
    while the Minkowski metric gives its relativistic generalization, the proper time

    dtau^2 = eta_(alphabeta)dx^alphadx^beta
    (5)
    = -(dx^0)^2+(dx^1)^2+(dx^2)^2+(dx^3)^2.
    (6)
    The Minkowski metric is fundamental in relativity theory, and arises in the definition of the Lorentz transformation as

    Lambda^alpha_gammaLambda^beta_deltaeta_(alphabeta)=eta_(gammadelta),
    (7)
    where Lambda^alpha_beta is a Lorentz tensor. It also satisfies

    eta^(betadelta)Lambda^gamma_delta=Lambda^(betagamma)
    (8)
    eta_(alphagamma)Lambda^(betagamma)=Lambda_alpha^beta
    (9)
    Lambda_alpha^beta=eta_(alphagamma)Lambda^(betagamma)=eta_(alphagamma)eta^(betadelta)Lambda^gamma_delta.
    (10)
    The metric of Minkowski space is diagonal with

    eta_(alphaalpha)=1/(eta_(alphaalpha)),
    (11)
    and so satisfies

    eta^(betadelta)=eta_(betadelta).
    (12)
    The necessary and sufficient conditions for a metric g_(munu) to be equivalent to the Minkowski metric eta_(alphabeta) are that the Riemann tensor vanishes everywhere (R^lambda_(munukappa)=0) and that at some point g^(munu) has three positive and one negative eigenvalues.


    http://mathworld.wolfram.com/MinkowskiMetric.html
     
  11. pmb Banned Banned

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    228
    Can you please explain what that’s supposed to mean? What is “-1 0 0 0” supposed to mean? The Minkowski metric is given by

    n_ab = diag(1, -1, -1, -1)

    where diag(1, -1, -1, -1) is a diagonal metric with the numbers 1, -1, -1 and –1 as the diagonal components. That means that the components of the Minkowski metric are n_00 = 1, n_11 = n_22 = n_33 = -1.

    A bit of advice – Your notation is very sloppy making it hard to understand. E.g, it took a few seconds to realize that alphabeta is really “alpha beta”. Not separating them makes if confusing to read. That’s what spaces are actually for.

    The same thing holds here

    dtau^2 = eta_(alphabeta)dx^alphadx^beta

    First off since you can’t use Greek letters then you shouldn’t spell them out. Use the convention that Wald does in his GR text. In his text he uses letters from the beginning of the alphabet such as a, b, c, etc. Also try using T instead of “tau” so we have instead

    dT^2 = n_ab dx^a dx^b

    which is much easier on the eyes.
     
    Last edited: Nov 18, 2013
  12. paddoboy Valued Senior Member

    Messages:
    26,023


    That is not my work, and I did give a link...here it is again....

    http://mathworld.wolfram.com/MinkowskiMetric.html

    It appears that in copying and pasting, it didn't transpose as it should have.
     

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