Yes, assuming the turnaround point has a clock Einstein synced with the start point, the traveler clock reads 20 seconds and the turnaround clock reads 40 seconds. I am also trying to figure out how to reconcile the traveling-twin's "telescope view" of the home-twin's clock with the two different times he must calculate for the home-twin's clock, before and after the turn around point. I remember doing a calculation like that a long time ago, but I can't remember what I did. I am currently working on it, and will post when I figure it out. For now, I may be wrong, but I think the time he sees in the telescope would be 40-34.64.=5.36. When I changed my scenario to match the scenario on Mike_Fontenot's website, the distance between the start and turnaround became 34.64 in the home-twin's frame, and 17.32 in the traveling twin's frame. Sorry, but that is all I have so far.