Let us imagine we have two stations 1 km apart. The train runs between the two stations at velocity v. The train driver measures the time interval between the first station passing his window and the second station passing his window. The train driver compares the time he measures with the interval shown on the station clocks which are synchronised in the station frame. The train driver finds that his elapsed time is less than the interval indicated by the station clocks by an amount we have calculated a few times already. We later learn the the train itself was 1km long and as the driver passed the first station he sent a stopwatch backwards down the train at velocity -v. In the train frame the stop watch has velocity |v| and using clocks synchronised in the train frame we can show that the stopwatch will run slow by the amount we have already calculated a few times - so relative to the station clocks the stopwatch runs even slower than the drivers own clock. Meanwhile, seen from the station frame the stopwatch travelling back down the train has velocity +v-v = 0 so runs at the same rate as the station clocks. The stopwatch is slower than the driver's clock. The stopwatch is faster than the driver's clock. I don't understand the question. Hello Mum.