got another complex analysis question for u guys and girls here. would 1^i = e^(-2pi), since e^(2pi*i) = 1, making 1^i = e^(2pi*i*i) = e^(-2pi) = 1 / e^(2pi). i tried it with my TI-83 calculator and it just gave me 1. so, which is it?

oh and "pi" = 3.14..., i don't know how to make the symbol so i just say "pi".

edit: i know this is probably wrong, but since 1 = e^0 = e^(2pi*i), wouldn't that make 2pi*i == 0, making 0 * i == -2pi?

oh and "pi" = 3.14..., i don't know how to make the symbol so i just say "pi".

edit: i know this is probably wrong, but since 1 = e^0 = e^(2pi*i), wouldn't that make 2pi*i == 0, making 0 * i == -2pi?

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