I am confident that if you ASSUME the Bohr model and adjust for the higher masses etc. then yes, you will get hydrogen like energy level structure. I prefer my approach, which first derives the force law for a symmetric version of Maxwell's equations. If it turns out to be simple inverse square (and I expect it may) then yes, the assumption of Bohr model and hydrogen like is justified; however, if it does not, because they are moving thru each other’s time-retarded, radial magnetic fields, (velocity dependent forces, etc., or any other reason) then the defect of your approach will be exposed.No the leading order calculation should be just as I described it. ...If you want to compute precision quantities, like the hyperfine splitting or some such things, then you will have more complex calculations. ... All you really have to do is take the Bohr model and generalize it.

I suspect monopoles also have a half unit of intrinsic spin, i.e. are Fermions, etc, but do not know if magnetic monopoles have intrinsic spin. I agree that if they do, then there will be a direct analogue of "hyperfine structure."

If they do have spin, then I think it will be a gross splitting of the normal two fold degeneracy (up & down spins that, for example, permits He atom to have both its electrons in the n = 1, l = 0 state and still keep Pauli happy.) I will call this splitting the "hypergross structure" as I would be very surprised if it not very large compared to "hyperfine structure" because rather than the weak interaction between the electron spin and the weak magnetic field of the nuclear spin, the monopole spin will be interacting with the strong magnetic field from the other monopole in the case of the postulated monopole atom.

We will just need to disagree on which is the superior approach to evaluation of these concerns (Your "assume Bohr like" or my "start with symmetric Maxwell's eq.") I am much to rusty in these calculations and now too lazy to do more than talk about it, but confident I am correct in principle. So we can drop this subject as far as I am concerned. (If you want the last word, be my guest.)

Thanks, but not now. About 25 years ago, when trying to struggle thru a paper (in Phys. Rev. Section D, as I recall) some more simple version would have been very welcome. (I lost interest in physics about 20 years ago, and now my intellectual efforts, such as they are, are related to how the mind functions etc.; but, I have become too lazy even in that, ever since I finally worked out, at least to my own satisfaction, how genuine free will could exist and yet be consistent with physics.)More about Hawking radiation:

People often claim that one can think of Hawking radiation as the splitting of vacuum polarization pairs---i.e. the electron falls into the black hole and the positron shoots off into space. I have done the calculation, and it is not clear to me that this is what happens. It seems perfectly reasonable to imagine this process, but the actual derivation of Hawking Radiation has nothing to do with vacuum polarization pairs, that I can tell. (I can give more details of the calculation if you are interested.) There is a book by Davies and Birrell called QFT in Curved Spacetimes where the calculation is preformed, I believe.

I have avoided stating that they have an EH. (Used expressions like "near the monopole atom, the gradient may be large" etc.)The second thing is that I am still unclear as to why a bound system of magnetic monopoles should have a horizon. Even if they are very massive, they are point-like objects---they are fundamental particles. To me, this seems like saying---electrons are black holes because they have an infinite density...511 keV in zero volume is infinite.

I think it posssible that an EH exists , because of their extreme mass, but we would need to find the separation of the momopoles in the ground state of the magnetic monopole atom to make an intelligent guess as to the existence or not of an EH. Not every respectable physicist accepts that even real BHs are the singularities that the mathematical BHs are. Certainly, it is conceivable that a N/S monople atom, if in a quantized, extremely small, ground state, could have an EH. I.e. look like a standard BH outside some distance from the CoM and (1) not be a true singularity and (2) not be able to radiate magnetic waves because it is in a quantized ground state. (Same reason the accelerating electon in the ground state of the hydrogen atom does not radiatively spiral into the nucleus in less than a nanosecond (I did that calculation years ago. - I forget the duration of the decay to a separation equal to the sum of their classical radii, but it is very very short.) I am not confusing HR with spectral line radiation and when you think about the fact that quantization also prevents the hydrogen's ground-state bound and accelerating electron from radiating you make understand why I think the same will happen in the ground state of the monopole atom (as well as effects I have also discussed on the conditions when HR is, or is not, possible from it. I.e. my equation M = Eg + En + En - E etc.)

You should have stopped when you were "even." - You are in error here.I'll try to clarify this again. Suppose you have a black box that may contain a black hole. Now, consider sitting outside of this box with a detector, and you only see one event---a photon coming from inside the box. Can you say that this photon is "Hawking Radiation"? For one, you don't know if there even is a black hole in the box. The only way that you could tell if there was a black hole in the box is to sit outside long enough and observe thetotalstuff that comes out. ...

Of course there are some practical strength and materials type problems with a big box that may or may not have a BH inside, especially as I wish that BH to have a surface temperature of 5000K, so it is a rather large box if the EH is far from the walls, as I also assume, but lets ignore all that, as it is a conceptual error you are making:

When there is equilibrium at 5000K, it is impossible to tell if there is or is not a BH inside the box from the radiation emerging from a tiny hole. - It will have Planck’s black body spectrum in either case.

However, take some advise from one who is probably several decades your senior. By posting here now, you are making

**a much more serious error.**- Turn off your computer and turn on that woman you said you went to visit.

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