Here are some links

Here is a very old java applet that you can use to add vectors and drag the arrows around and then calculate the resultant. You can continue to drag the arrows around after the resultant has been calculated and it will update in real time. Since this one doesn't give you the ability to set the exact magnitudes or angles of the vectors, you'll have to approximate.

http://www.walter-fendt.de/ph14e/resultant.htm
Here is another visual one, but this one will let you see the numbers representing your vectors. However, the scale isn't exactly what we need in order to display the vast differences in magnitude of the vectors. It's still a bit useful because you can put the vectors anywhere on the grid.

http://phet.colorado.edu/en/simulation/vector-addition
Here is the calculator I used to get the actual numbers

http://www.1728.org/vectors.htm
Since these are all 2D, you'll probably want to pick a point on the Earth at a time when the Earth, Sun, and Galactic center line up, which happens sometime every December. I chose the Equator at midnight so that it is facing away from the galactic center

Here are the angles and magnitudes of the major vectors relative to the Earth's orbit on ecliptic plane.

~225km/s @ 120 degrees - Earth around the Milky Way.

29.7km/s @ 0 degrees - Earth around the Sun.

0.465km/s @ 336.56 degrees - Rotation of the Earth.

Calculating these should give you 211.38km/s at 112.94 degrees.

Edit: I used this acceleration calculator to, well, calculate the acceleration

http://www.smartconversion.com/unit_calculation/Acceleration_calculator.aspx
Initial speed (v0) = 0

Final speed (v1) = 211.38km/s

The Time (t) = 359.0170848 minutes

Calculation result = 9.81290347773444m/s^2

I used this online trigonometry thing to help me visualize the changes in speed of a point on the surface of the Earth as it rotates as well as the whole Earth as it revolves around the Sun.

http://www.touchmathematics.org/topics/trigonometry
I found that if I move the "dial" to 45 degrees, it gives me the best point to start from (which is still going to be the same point on the Equator I mentioned above, I just shift it in my mind so I have a good visual representation). I use the COS and SIN lines to visualize the changes in speed in the different directions. I also use this to help me imagine which directions I am slowing down or speeding up a ball in when I throw it straight "up" or outward from the center. I see that I am slowing it down about half of the magnitude of my throw in the COS direction and speeding it up about half the magnitude of my throw in the SIN direction. I don't slow it down at all in the TAN direction because it is perpendicular to my throw. I also slow the ball down a little bit in the direction the Earth travels around the Galaxy and speed it up and down in the SIN and COS directions of the Earth traveling around the Sun. So, when you throw something straight up or when something falls straight down, it will still impact the Earth because of the way the Earth moves.

If you need help visualizing how this could create the normal force on your body against the surface, think of the Earth constantly "throwing" you tangent to its rotation. This is where the mass of a planet vs the mass of your body come into play.

The more massive a planet is, and the faster it rotates, the more momentum it is going to have when it collides with your body after this "throw". The inertia of the planet and the inertia of your body create the normal force during this collision.

The speed of a planet's rotation is also what helps it grow to a great mass. The faster a planet rotates, the harder the collision will be as it "throws" less massive bits of space debris into its surface while it "clears its neighborhood". It also makes it harder for those bits to fly off the surface into space. This works best with inelastic collisions for obvious reasons, but will also work with elastic collisions as the object will lose momentum every time it collides with the surface.

The more massive the planet is, the more momentum it has, and the more massive the bits of debris it can keep on its surface. It's like a Katamari Damacy.

Now do you see it the way I see it?l