Is this real maths or somebody winding me up?

Lol, thank you for replying. I think the Cartesian coordinate system is easy enough to understand, it is basically just different points inside of a box. It seemingly gives the dead centre of the box a 0 position value (the observer) , then minus and plus vector values ''expand'' from this point.
I am yet to understand how this works though, if the box is in motion.

:) Points in a box, Schroeder's cat in a box

Dead centre - dead cat

As my recently dead mate used to say

DNDK - Don't Know Don't Care

:)
 
What science is your interest?

Time is the main one

Physics

Evolution

At the moment I am trying to get through a book Concessness Explained

However I am not a fan of the author's writing style so it's a hard slog

:)
 
Time is the main one

Physics

Evolution

At the moment I am trying to get through a book Concessness Explained

However I am not a fan of the author's writing style so it's a hard slog

:)
Time is one of the easiest subjects to learn and understand. To understand Physics , there is a need to know what the math's means at times. For example in this thread I am trying to learn to accurately describe something. In my terms

Δ<[]> = Δu = c ~ 1/a

<[]> =empty matrix span

u= internal energy

c ~ 1/a = inversely proportionally when c

Words alone don't explain something. I am trying to explain with this , '' gone in a flash ''. However this is probably meaningless , so I need to learn the correct math to explain it better. Maths just explains physical process.
 
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I am also trying to explain that u.v = a[0,0,0]+b[0,0,0,]=<a.b>=1

ab

What is true for a is also true for b.




This means the dot product of simultaneous actions of Δ<[]> = Δu = c ~ 1/a, at the exact same point and time in space, result in nothing becoming one. So I need to learn more math to explain better.

In added example ; (A) , if we define (A) to be a 3*3*3 mono-pole matrix, all positional points of the matrix will be in a state of expansion and transpose .

Using a Cartesian coordinate system of course.

added- and of course u.u=m
 
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Time is one of the easiest subjects to learn and understand
OK

I'll go first

Be aware I have a 3 Ping rule. I'll give you 3 Pings. If I feel response not good enough most go on iggy (don't ask work it out)

If not iggy I dummy spit

OK let the fun games begin

First Ping

TIME does not exist

Tell / explain / convince me it does

You are in the deep end. Are you going to sink or swim?

:)
 
OK

I'll go first

Be aware I have a 3 Ping rule. I'll give you 3 Pings. If I feel response not good enough most go on iggy (don't ask work it out)

If not iggy I dummy spit

OK let the fun games begin

First Ping

TIME does not exist

Tell / explain / convince me it does

You are in the deep end. Are you going to sink or swim?

:)
Time is a word we give to something, how can it not exist if we are defining the word for the existence of something?
 
Schroeder? Who he?

Schrödinger's cat (but I guess you knew who I ment)

Since my spelling is attrochous - atrocious I tend to rely on spell check. It came up with Schroeder - I took it

:) Don't pick on this poor dyslexic speller :)

IMG_20180206_013444.png
And I guess you recognise this Schroeder

Cheers


:)
 
Time is a word we give to something, how can it not exist if we are defining the word for the existence of something?

You waisted one Ping - ie I required a explanation of its existence, not a question about why it couldn't

Second Ping

TIME is a CONCEPT

Concepts do not have physicality

ie they don't exist

Again (you said it was easy)

Tell / explain / convince me it does

:)
 
Lol, thank you for replying. I think the Cartesian coordinate system is easy enough to understand, it is basically just different points inside of a box. It seemingly gives the dead centre of the box a 0 position value (the observer) , then minus and plus vector values ''expand'' from this point.
I am yet to understand how this works though, if the box is in motion.
It makes no difference if the box is in motion, the motion of the box will have no effect on the calculation of the location of points in the box.
 
HUh, all the other people said is gibberish?
All the words were gibberish, and the paragraph reads as intentionally comic. Some of the symbolic equation stuff was close to being sensible with a couple of tweaks, as arfa provided, if you ignore the words.

You are setting yourself a tough goal, if you intend to learn not only new and difficult subject material but new and difficult material embedded in reams of gibberish and parody.
 
All the words were gibberish, and the paragraph reads as intentionally comic. Some of the symbolic equation stuff was close to being sensible with a couple of tweaks, as arfa provided, if you ignore the words.

You are setting yourself a tough goal, if you intend to learn not only new and difficult subject material but new and difficult material embedded in reams of gibberish and parody.
I think I already understanding the basics , I do know it is rather technical and there is extensive learning, more than basics.

I do not observe any gibberish apart from maybe my own gibberish.

I will keep learning , in saying that does <[]> show an empty matrix span?

Does , <{{0,0,0}{1,1,1}}> show an expansion ?
 
Schrödinger's cat (but I guess you knew who I ment)

Since my spelling is attrochous - atrocious I tend to rely on spell check. It came up with Schroeder - I took it

:) Don't pick on this poor dyslexic speller :)

View attachment 1841
And I guess you recognise this Schroeder

Cheers


:)
And spell check didn't scream about "Concessness"? You need a new spell check.
 
Thank you.

If I specified [0,0,1] that would be one position outwards on the z vector?
That point in Cartesian coordinates system would be at 0 on the x-axis, 0 on the y-axis and 1 on the z-axis.
Your use of the term vector doesn't make sense in the context you presented.

There are many ways to represent a vector. You could say that you have a vector a, defined as a = [0, 0, 1], which would be a vector of length 1 in the z direction. This particular vector is also known as a unit vector in the z direction; $$ \hat{k}$$
 
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