Well,
The release of radioactive material is most concentrated within the 30 mile radius of the Nuclear Facility, This area is about 2,827.432 square miles. radiaoactive material has fallen in this area in groups or plumes and it seems that these subgroup areas within the 30 mile radius would be sprayed with the poly-resin suggested by TEMPCO to hold radioactive material in place and prevent spreading.
To spray a poly resin over a area with a 5.7 miles radius having a area of 102.07 square miles and within the 30 miles it would require 24,898,631.73 gallons of resin to effectively cover such a area. The Leaf Surface Area is 5,691,115,823 square feet at full growth for the area, the ground surface area is 4,268,336,867 sq. ft. for a total of 9,959,452,690 sq.ft. that can be sprayed. 2,845,557,911 sq.ft of area will avoid the spray due to defelection, this also will be the Surafce Area containing or trapping cesium and other vapors rising in the area during summer time.
The area will produce about 1.707334394 x10^10 pounds of vegitation, and by fall in September it will shead in leaf fall resulting in 1,021,601.728 tons of carbon that will cover and react with the radioactive material released from the Nuclear plant.
At low estimate of 2.153284 tons of radioactive by product has been released, 50% of that material has fallen within 30 miles resulting in about 7.50316853 x 10^19 vapor plumes of cesium, and 6.587095495 x 10^15 vapor plumes of Iodine, other material exist to be released and are assimulated in to the above vapor plumes or clouds.
Cesium plumes overlap falling in a area with a 5.7 mile radius resulting in surface deposits of about 792,570,795 cesium atoms forming a molecule about 9.375 micrometers in diameter,once setting down the molecule begins to divide and seperate untill it froms daughter molecules of about 1.12 nanometers (95,311 cesium atoms), it is this nanomolecule that exist within the depth of soil.
Iodine plumes falling in the same area result in surface deposits of about 9.816096728 x 10^12 iodine atoms forming a spanning moluecule of about 11.5 centimeters or gas group. if the iodine can condense and sperate it will try to form a daughter molecule or cluster of about 55.4 micrometers (containing about 1,180451,681 atoms).
In smaller sub-group deposits of half the radius,the above figures can be multiplied by 4. For each onehalf of the radius multiply by 4 to give the result and particle size for that area as well as leaf area to calculate the rainwater transit, for example to find the figures for a area with a radius of 2.85 miles or a diameter of 5.7 miles multiple by 4 (the leaf surafce area figure is adjusted for the area near the nuclear plant accounting for crop leaf and tree leaf so can not be magnified to areas with greater diameter than 60 miles).
In a even distribution over the radius area of 30 miles or 2,827.432 square miles there area 1 cesium atom per 127 area atoms,and 1 Iodine atom for each 117 non-radioactive atoms in the area.
DwayneD.L.Rabon