Mechanics of Gravity

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[francescakat]

Without gravity on Earth life wouldn't exist.

 

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Welcome to the forum.

So let us create motion; let us stretch forth our hand and create a spherical void in the midst of this infinite ocean of aether. When we draw back our hand, we see that the aether instantly, and with ever increasing acceleration, begins to collapse back into the void attempting to reoccupy it. But the stress of immense acceleration destroys the aether converting it into radiant energy which radiates outward and away from the void.

So if the aether is accelerated to some undefined level there is some sort of stress applied to the aether and it is converted to energy. What is the accleration, what are these stresses, why does the energy radiate away from the void? How does this not violate the conservation of mass and energy?

We now need to take some measurements and see just what it is that we have created.When we take our measurements we see that, when the aether arrives at the surface of the spherical void and is converted into radient energy, the aether is moving at c meters per second. Its acceleration rate is c2 meters per second per second.

Huh? If it is accelerating at twice the speed of light that means motionless aether will reach the speed of light in 0.5 seconds - and will stop accelerating?

Newton and Einstein have equations to describe the force of gravity in their universe. So lets formulate some equations.
Let:
g = gravitational acceleration
r = radius of gravoid = 1.11446399 x 10-27 meters
d = distance from center of gravoid.
c=speed of light

What led you to pick this particular value for the radius of a gravoid?

We now need some way to compare our equation with Newton’s and Einstein’s equations. They use mass and the gravitational constant G in their equations. The value of G is 6.7384 x 10-11meters per second per second and it is equal to the gravitational acceleration in the gravitational field of a 1 kilogram mass at a distance of 1 meter from center of mass. A void that would generate gravitational acceleration equal to G at a distance of 1 meter would have a radius of 2.725999 x 10-14 meters. That means that if all the gravoids in a 1 kilogram mass were fused together into one spherical void, that is what its radius would be. So we will let rk equal the radius of a 1 kilogram spherical void and that will be our conversion factor.

That is based on the assumption that the radius of the gravoid has some physical meaning and was not just picked out of the air. A suspicious person might think you piced the radius of a gravoid to make these other numbers work out...



You wrote
$$E = mc^2 = \frac{c^2r^2}{(r_k)^2$$

Which is strange because $$mc^2$$ has the units of $$\frac{kg-m^2}{s^2}$$

And $$ \frac{c^2r^2}{(r_k)^2$$ has the units of $$\frac{m^2}{s^2}$$, which means they cannot be equal and your equation is not even energy.

The value of G is 6.7384 x 10^-11 meters per second per second and it is equal to the gravitational acceleration in the gravitational field of a 1 kilogram mass at a distance of 1 meter from center of mass.

No that is not right. G has the units of $$\frac{m^3}{kg-s^2}$$, not $$\frac{m}{s^2}$$, nor is G "equal to the gravitational acceleration in the gravitational field of a 1 kilogram mass at a distance of 1 meter from center of mass".


The rest of the paper fairs no better I am afraid.