2inq, your "clock scheme" is three clocks at rest and in the same place in the same reference frame. Suggesting that this "does away with relativity of simultaneity and length contraction" is just stupid. If you want to just declare that the the tank isnt length contracted, go ahead... but trying to prove SR to be incorrect by assuming it to be incorrect is again just stupid.

You asked what SR predicts. Dale told you. I told you. If you didn't follow it, ask for clarification.

If you 'contract' the lengths of the tank and tread in the ground frame, the clocks on the tank will read wrong. For instance, if you state the distance between the moving axels is only 10 meters in the ground frame, the tank clock will only accumilate 1/4 the time as the ground clock to travel the 10 meters.

It's clear you are either unwilling or unable to work this through properly.

Here's what SR says happens with your three new clocks. I have worded these answers carefully for a reason, so be careful about what you read into them. In particular, be careful about simultaneity. Assuming very small wheel radius:

1) In the ground frame, a clock attached to the tread will be on the ground for 11.7ns, it will tick over 11.7ns in that time, and the tank will move foward 10 feet.

In the tank frame, it will be on the ground for 23.5ns, it will tick over 11.7ns in that time, and the ground will move back 20 feet.

2) In the ground frame, a clock on the axle will tick over 5.87ns in the 11.7ns it takes for the tank to move forward 10 feet.

In the tank frame, it will tick over 23.5ns in the 23.5ns it takes for the ground to move back 20 feet.

3) In the ground frame, a clock on the tread will be off the ground for 82.2ns, it will tick over 11.7ns in that time, move forward 80 feet, and the tank will move forward 70 feet.

In the tank frame, a clock on the tread will be off the ground for 23.5ns, it will tick over 11.7ns and move forward 20 feet in that time, and the ground will move back 20 feet.

If you are unsure how I derived these results, please let me know. I may have made a mistake. We can work through a Lorentz transform for each event of interest to find out.