You agree that the energy must reside somewhere...but velocity is purely relative.
So is the energy. Like I said, energy is not the same as the full stress-energy tensor. It is just one aspect of it. More precisely, the local energy density is one of the ten components of the stress-energy tensor field if you decompose it in an inertial coordinate system.
Considering the energy and ignoring everything else would be like taking Newtonian mechanics and considering only the $$x$$-component of the force, and then wondering how Newtonian mechanics can respect rotational symmetry when the $$x$$-component of force depends on the coordinate system.
What if the Earth was object A and object B was an interstellar mass from deep space, traveling at a substantial fraction of c? Would the stress-energy tensor reflect this energy in us, particularly prior to our knowledge and measurement of object B?
No, it just depends on the reference frame. In something like the rest frame of object B then yes, Earth has high energy and nonzero momentum. In the rest frame of Earth, it is interstellar object B that has high energy and momentum and Earth just has its normal rest energy. But the full stress-energy tensor field, which is what the gravitational field is coupled to, is covariant and is the same tensor field in either case.
Unfortunately, I did not get to electromagnetism. I took a single Physics course at UNL before I decided that juggling three kids and a mortgage and night classes was too difficult.
Okay. That makes more sense.
I will definitely look at the EM analogy though; my immediate response is that the paradox won't exist in EM because we don't have an analogous blackhole to contend with. Remove the blackhole from GR and any contradictions go away -- the location of energy is irrelevant.
Huh? Even regardless of black holes, the gravitational field is not the same everywhere. It tends to be stronger near where you have matter and it tends to be weaker far away from matter. It also depends on how that matter is distributed and what it is doing and how that is changing over time. E.g., the gravitational field around a rotating mass is not the same as it is around a nonrotating one. The gravitational field around two objects orbiting each other is different still; for example, the objects emit gravitational waves in that case. Obviously GR has to be able to model and predict this. There is nothing special about black holes here.
Object A claims that object B has momentum energy; object B claims that object A has it; the remote observer C could claim that the A-B "system" has such-and-such energy. This would hold true even if A and B were in a tight, mutual orbit, with sufficient angular momentum to traditionally predict the black hole. According to A, they are merely "free-falling" with B buzzing around at terrible speeds. It doesn't really matter because all of the energy effects would be observed as predicted for all parties. Relative energy would have relative energy-related effects that are on a continuous, sliding scale devoid of one-way thresholds.
Again, the gravitational field does not in general depend only on the "energy" or the "momentum" but on the stress-energy tensor field, which is a covariant object. When you see simple thresholds like "you get a gravitational field if the energy is greater than $$M c^{2}$$" it is not a general thing in GR. It is a different type of thing where a human theorist has come along and worked out what happens in a specific situation, under a lot of constraints, often working in a particular reference frame from the very start (so the result is not expressed in a frame-independent way but specifically for whatever frame the theorist is using) and often choosing to introduce simplifying approximations (e.g., pretending a few nearby masses are the same as one aggregate mass, even if that is not exactly true).
Black holes still make no difference here. The gravitational field is described by a manifold, which does not depend on the reference frame, whether it contains a black hole or not. A number of key measures of the gravitational field strength, particularly the curvature tensors, are covariant; they do not depend on the reference frame. So GR predicts the gravitational field in terms of the stress-energy tensor, which includes energy and momentum and so on which are individually frame-dependent, but it needs to do so (and it does) in a way that, in the end, respects the coordinate-independence of the theory. This problem of coordinate-independence and how it is handled and solved in GR has nothing special to do with black holes. It exists anyway.
Anyway, I will accept at face value that the black hole is a valid solution to Einstein's field equations. I haven't really pointed out that the black hole creation has not been shown to be a valid solution.
No, that's also been modelled. E.g., the Tolman–Oppenheimer–Volkoff equation models the process of a sphere of fluid (how cosmologists model stars) collapsing over time and forming a black hole. It is derived by solving the Einstein field equation together with an equation of state for the fluid (this models physical aspects of the fluid, like how its pressure changes when it is compressed), so the gravitational part of it is an exact solution to the Einstein field equation.
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