The effect of the Doppler effect on planetary orbits

You don't know what a gravitational field is then. It isn't a force field. A massive object generates no force. For instance, let's consider just the sun without any planets. What force do you thing it generates?
There are no iron lumps near the magnet. Does this mean that the magnetic field does not exist?

Density is some kind of concentration of something per volume. So again, what might the 'spatial density' be say a million km from the surface of the sun? If you can't answer that (and give it meaningful units), then this explanation also is meaningless.
Spatial density is the concept of GR, why should you object? Space bending is a 2D image. In the perspective of a 3D image, it is the spatial density.

None of the above stuff mentions waves, so this irrelevant conclusion totally doesn't follow. To summarize what you cannot hear: No waves, no Doppler.
LIGO would not be happy to hear this.

You (Tony) are indeed not accepting feedback. Gravitational waves do not transmit gravity. The two are unrelated. You're incapable of hearing this.
You're taking a term you heard somewhere and thinking the two were the same. They're not. The sun exerts gravitational force on objects nearby. It emits negligible gravitational waves because it has negligible acceleration. Gravity is a function of mass. Gravitational waves are a function of mostly acceleration, and hence Earth generates more (about 200 watts) than the sun . Hydroelectric power plants harvest the energy of gravitational potential, and they could not generate all their gigawatts if Earth gravity only produces 200 watts of it total.
Gravitational waves are incredibly weak, and it takes an amazingly sensitive instrument like LIGO to detect it, and even then it only detects sources that actually generate significant waves at supernova energy levels.
Gravity on the other hand just requires something simple like my bathroom scale.
What is the reason for the difference in acceleration? You should understand that the two locations A and B will not have different g1 and g2 for no reason. Have you thought about the reason?
The gravitational waves discovered by LIGO are very weak. He comes from a distant place, so how can you ignore the gravitational field of the earth in front of you?

No. A large mass moving from A to B is the same as a large mass not moving at all in a different frame. No waves involved in this.
If you can argue this point, you will get a Nobel Prize.

Again, but considering them in a frame where they're not moving. Velocity is not a property of an object. It is a relation with some reference.
A gravitational field is not an object at all. A field (any kind of field) is an abstract value that varies over location. By definition, a field doesn't have a velocity since it has no defined location. You are treating it as an object with a location, which violates the definition of a field.

So making a field static is a simple as considering the field in a frame where the thing generating the field isn't changing.
Is GR afraid of moving?
The Doppler effect itself is based on the theory of classical physics. Where do you say these meanings? What you want to explain is that there is no gravitational field. That is, it is only the space that bends, which causes the gravitational wave. . . These are just models, I also appreciate the GR model, but if the GR model is the only model that can be used, then I do not agree with you.

Don't you think that if the motion of the earth gives rise to gravitational waves, as you suggest, then LIGO should have detected them? I mean, they would be right on the doorstep.
In the calm sea, there is no outside influence, how can there be fluctuations, how can you throw an ant into the waves. Since the waves have been stirred up, it must be a force that cannot be ignored. It is certainly not an ant.

Let's look at the neighbor of the earth, the moon, and the gravity of the moon is also affecting the earth. So how much do you think the acceleration g produced by the moon will be measured at the position of the earth? Almost 0.

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There are no iron lumps near the magnet. Does this mean that the magnetic field does not exist?
No but it means there is no force. Which is what he said.

Tony, you really are not much good at this. You clearly don't understand what a field is. Even worse, you can't even read a post of mine in plain English without trying to reverse its meaning.

I suspect you are suffering from some form of mental condition.

In the calm sea, there is no outside influence, how can there be fluctuations, how can you throw an ant into the waves. Since the waves have been stirred up, it must be a force that cannot be ignored. It is certainly not an ant.
Gibberish.

I suspect you are suffering from some form of mental condition.
You are no longer suitable for discussion on this topic. Even a person who does not have at least a respectful attitude, I hope you leave this thread.

2. Due to the large mass object, the spatial density is changed, thus generating gravity.
No matter what kind of model can produce wave effect, wave Doppler effect.
Gravitation waves are not emitted from stationary objects with constant mass.

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There are no iron lumps near the magnet. Does this mean that the magnetic field does not exist?
Like a lake with no wind, the field exists, but it is calm - no waves.

Is GR afraid of moving?What you want to explain is that there is no gravitational field.
Gravitational fields do not, in and of themselves, have waves. Only changes to the gravitational field propagate as waves.

The planets experience no gravitational waves from the sun. They are effectively sitting on a calm lake.

It doesn't matter whether you agree with this, or even understand it, your idea is based on faulty assumptions.

Gravitation waves are not emitted from stationary objects with constant mass.
My thoughts are consistent with yours. At least it is moving relative to the earth.

The planets experience no gravitational waves from the sun. They are effectively sitting on a calm lake.
I totally agree with you.
Your thoughts do not conflict with the Doppler effect of gravitational field.

Regardless of whether it is a gravitational field or a curved space, no matter what it is in the end. What matters is that it has an effect on the physics in which it is located. And this action follows the movement of objects.
Then the fluctuation of the effect caused by this movement, no matter what it is called, it will also have a Doppler effect. The effect of relative movement.

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Tonyuan has no intention of considering any point you make.

The ignore button is your friend. Bye Tony...

Why don't you simulate it like I did? Verify the motion of celestial bodies under the Doppler effect of gravitational field.

Tonyuan has no intention of considering any point you make.

The ignore button is your friend. Bye Tony...
Can you specify?

Is my explanation not clear enough?
==>Regardless of whether it is a gravitational field or a curved space, no matter what it is in the end. What matters is that it has an effect on the physics in which it is located. And this action follows the movement of objects.
Then the fluctuation of the effect caused by this movement, no matter what it is called, it will also have a Doppler effect. The effect of relative movement.

The model is not important.
What is important is that the planetary motion is affected by somethingX, and this effect will change as this thingX changes.

I think what I have said is clear enough, I do n’t know why you still do n’t understand. You can look at the GR calculation to find the planetary precession deviation. Except that Mercury is in line with the observation results, the precession deviation of the other planets is not a little bit worse than the observation results.

Once my Polish colleague had a very hidden error in a program design. If you don't think very carefully, you can't find a logic error here. Although this procedure has been considered correct for more than 3 years. But I found this error and told them that the design was wrong, and made a detailed explanation. But they totally disagreed with my point of view. I explained to them many times, and finally they were very angry and very unwilling to listen to me for 10 minutes. Then they said sorry to me, they were wrong. After correcting this error, 100 prontos have been resolved, and the performance of 4G devices has been greatly improved.
History always needs to repeat itself.

You are no longer suitable for discussion on this topic. Even a person who does not have at least a respectful attitude, I hope you leave this thread.
You have done nothing to earn respect from anybody. In fact your refusal to answer the question everyone has been asking you - a question that is obviously demanded by the title of the thread, shows a total lack of respect on your part.

Either you are both rude and an idiot, or you have a mental condition. By suggesting the latter I am being charitable.

But Origin is right.

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