Twin paradox (Pete and MacM)

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MacM said:
Simple if A is v = 0 then B has a relative velcoity to A of 0.9c.

If B v = 0 then A has a relative velocity to B of 0.9c.

That is why it is called Relativity or relative velocity.

WRONG! The direction of velocity cannot be the same. One of the velocity must be negative!
 
James R said:
MacM:

In my thread which discussed the derivation of SR, I never specified that either car was stationary. Such an assumption is not necessary. There is no absolute standard of rest.

So now you want to claim that Relativity does not hold that each and every observer sees himself as at rest? Good luck with this bullshit. I feel very confident that many here are actually starting to see through this "Blue Wall""

addressed the issue multiple times. In fact, you have ignored some of the posts I have made on the topic. I specifically addressed your point in a post about one page back in this thread, which I can only assume you did not bother reading, since there was no reply to any of the comments I made there.

Let's face it. All you are doing now is backing away from anything solid. Since it was proven that your detailed scenario did not do what you claimed, you have presented a number of vague, shady alternatives with ill-specified conditions. You have taken to posting one line assertions without proof, as if they are worth something.

Your new scenarios keep shifting the ground backwards and forwards. One moment, you have one light signal; the next you have two. One moment you insist on viewing the clocks from a reference frame half way between them; the next you insist on viewing them from one clock's frame. Your proposed methods of stopping and starting the clocks are all over the place, generally not specified at all.

What it comes down to is what I said before, but you ignored. All your recent efforts essentially amount to: MacM sets the time on a clock. MacM later reads off the time he set + some predetermined amount. MacM claims his reading says something about relativity, or "reciprocity" or some spur-of-the-moment meaningless MacM concept.

At the start of this thread we had the potential to create a scenario which would be useful for actually reaching conclusions. Now, we just have vague, useless statements, plus a load of "you said - I said - you haven't proven - I have shown - you're a liar - no, you're the liar" bullshit.

Well, well, well. You just can't give up with the unsupported attacks and outright "LIES" regrading things I have said and supported. You sir are a deliberate liar, I regret that but seems to be obvious at this time.

You have nothing solid.
You have no mathematics.
Your claims are unsupported.
You have proven you can't even be consistent with your own views.
You have a shocking memory for previous points which have been discussed in full.
You have shown that you don't even have the ability to understand relativity, let alone refute it.
Your definitions are so vague as to be utterly meaningless.
You can't even set up a consistent scenario without changing it every 2 minutes.
You ignore all points you'd rather not see.
You constantly misrepresent other people's statements.
You put words into people's mouths which they never said.
You twist and turn and bait and switch.

Challenge:

Post a scenario (anything you like) and analyse it mathematically to show either:

A. The correct result is not the same as the result relativity predicts, because the
perceptual outcome is not the same as the real outcome.

OR

B. Applying the theory of relativity results in a true self-contradiction, which invalidates that theory.

Put up or shut up.

I have many times and you have even agreed in the past very specifically to the issue raised here but now you choose to try and ignore the facts and to post horseshit.

Sorry it no longer sticks to the wall. You clearly have no answer or refutation of my facts. You are a loser. A bad sport loser but a loser none the less.

http://www.sciforums.com/attachment.php?attachmentid=3347&stc=1

Constant relative velocity has been and remains the only issue I have raised. The rest is irrelevant bullshit in an attempt to confuse the issue. Do you retract your above concession? Are you going to flip-flop once again in an effort to save your precious Relativity?

This is hillarious I have not argued the affect is not seen I have shown clearly that it simply only preception and not reality. You have agreed that there is no net affect in constant velocity cases and yet you want to argue, argue and argue horseshit which has nothing to do with my posts or the issue at hand. Stick to the issue.

Take a position and defend it with actual proof. Every post attacking my understanding, altering my statements claiming they mean something different than was clearly stated, grasping onto typo's and trying to claim it as evidence of misunderstandings when infact I have typed the same point numerous times correctly and/or used the formula's many times to produce correct calculations many times and calling me a liar shows just how weak your position is.

Your above concession it absolutely on point and covers the entire topic of this debate. My view is valid, PERIOD. END OF ARGUEMENT. Move on.
 
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WRONG! The direction of velocity cannot be the same. One of the velocity must be negative!

Now I am a little confused with this.

A sees B as velocity 0.9c because A is deemed at rest. But B sees A "receeding" at 0.9c and if B is deemed at rest then why would A's recession be considered as negative velocity.?....for all intents and purposes it is receeding from B at the same velocity as A is.

Look one way and look the other the velocity would be the same would it not?
[assuming no other reference frames were available]
 
QQ:

Velocity is a vector. It has direction and magnitude. The magnitude of the velocity is called the speed. An object can have constant speed yet changing velocity.

If A's velocity relative to B is v, then B's velocity relative to A is -v. Both have speed v=|v|.
 
ahhh....I see......I'll be......ha....I automatically assumed velocity was just another word for speed....boy, that's an opener.....ha!
 
Paul T said:
WRONG! The direction of velocity cannot be the same. One of the velocity must be negative!

And I would assume you have posted what you think is a clear differance. Please advise readers that (-X)<sup>2</sup> = X<sup>2</sup>.

Or are you that inept to not understand that.
 
MacM:

It seems everything has to be explained to you three times, when once is enough for just about everybody else. And even then, you're usually incapable of appreciating the point. Maybe I use too many big words for you. I don't know.

Your current fixation appears to be my purported "admission" that you were right and I was wrong all along. Unfortunately, that is a dream of yours. Once again, let me explain it for you, using small words.

1. In a symmetrical situation, it is quite possible to have 2 clocks record the same time.
2. The 2 clock example we have been discussing for most of this thread is not symmetrical.
3. Whether or not the 2 clocks record the same time depends on when they are started and stopped, obviously.
4. For most of this thread, we have been discussing a situation where the clocks are not stopped simultaneously in at least one of the two frames.
5. My "admission" you are so proud of referred to a symmetical situation. I have posted that situation in detail previously.
6. You confuse the two situations, just like you confuse everything else.

Poor confused MacM.

In my thread which discussed the derivation of SR, I never specified that either car was stationary. Such an assumption is not necessary. There is no absolute standard of rest.

So now you want to claim that Relativity does not hold that each and every observer sees himself as at rest? good luck with this bullshit. I feel very confident that many herre are actually are starting to see thirough tis "Blue Wall""

You're raving.

Look at what I wrote, then look at your reply. Did I say that relativity does not hold? No. Did I say that each observer does not see himself at rest? No.

You're putting words into my mouth that I never said. You're in fantasy MacM la-la land.

Your fantasy may be easy to refute. My words are quite another matter.

Challenge:

Post a scenario (anything you like) and analyse it mathematically to show either:

A. The correct result is not the same as the result relativity predicts, because the
perceptual outcome is not the same as the real outcome.

OR

B. Applying the theory of relativity results in a true self-contradiction, which invalidates that theory.

Put up or shut up.

I have many times and you have even agreed in the past very specifically to the issue raised here but now you choose to try and ignore the facts and to post horseshit.

No response, as usual. You don't answer because you can't answer.

Waffle on, MacM. I know that nothing I say will make the slightest shade of difference in your fantasy land.
 
Quantum Quack said:
Now I am a little confused with this.

A sees B as velocity 0.9c because A is deemed at rest. But B sees A "receeding" at 0.9c and if B is deemed at rest then why would A's recession be considered as negative velocity.?....for all intents and purposes it is receeding from B at the same velocity as A is.

Look one way and look the other the velocity would be the same would it not?
[assuming no other reference frames were available]

You are absolutely correct in the outcome. However they do generally refer to +/- velocities. But as I have point out to Paul T above (-X)<sup>2</suo> = X<sup>2</sup>, it is a nonsense distraction from the actual situation. It meaningless dribble.

It changes nothing.
 
James R said:
QQ:

Velocity is a vector. It has direction and magnitude. The magnitude of the velocity is called the speed. An object can have constant speed yet changing velocity.

If A's velocity relative to B is v, then B's velocity relative to A is -v. Both have speed v=|v|.

Which is technically correct but changes nothing in the resulting calculations.
 
Quantum Quack said:
ahhh....I see......I'll be......ha....I automatically assumed velocity was just another word for speed....boy, that's an opener.....ha!

And do you understand that mathematically (-X) *(-X) = X * X? That this issue is a red herring.
 
QQ:

Physicists tend to use some words much more precisely than the common usage of those words by people in their day to day lives.

Most people don't distinguish speed and velocity. Physicists do. There are also important differences between momentum and inertia, distance and displacement, rotation and revolution, mass and weight, to take a few examples of words many people use interchangeably.

Other terms in physics have very specific meanings, which become much more generalised in common understanding. "Energy" is probably one of the most abused terms in physics. Most non-physicists use that word to mean all kinds of things which have nothing at all to do with the physical definition of the word.

It is very important when having discussions of physics to know or to learn the technical meanings of words. If you don't know, then you often miss important parts of physical reasoning, or you can misinterpret concepts. This is one of MacM's major failings. He uses terms such as "reference frame", which sound technical, without actually knowing what they mean. The end result is that his use of the term does not match the technical meaning of the term, and so he continually makes statements which are incorrect, based entirely on his inability to understand the concept.
 
It is very important when having discussions of physics to know or to learn the technical meanings of words. If you don't know, then you often miss important parts of physical reasoning, or you can misinterpret concepts.

This I think is the most important thing that has been said the entire thread...certainly for me any way.

The interesting thing i have been thinking is

If we take two objects A and B and place them in a void of nothing and they are separating at a speed of say 0.9c how are we to determine which has negative velocity.?

Do we arbitarilly choose one object over another or is there some other means that I can't see?
 
James R said:
MacM:

It seems everything has to be explained to you three times, when once is enough for just about everybody else. And even then, you're usually incapable of appreciating the point. Maybe I use too many big words for you. I don't know.

Your current fixation appears to be my purported "admission" that you were right and I was wrong all along. Unfortunately, that is a dream of yours. Once again, let me explain it for you, using small words.

1. In a symmetrical situation, it is quite possible to have 2 clocks record the same time.

Your words should match your level of competance. NOt only "CAN" two clocks record the same time, they "DO" record the same time because your symmetry is not at issue "Reciprocity" is. And in reciprocity even asymmetrical motion (as in acceleration) the consequence of computing affects from each observers view nullifies any net change or result.

Give it up. You are boxed in. Stop trying to confuse jpeople that a one sided view or calculation has any merit in a discussion regarding "Reality". It is only an expression of a moving observers "Illusion" a perception.

2. The 2 clock example we have been discussing for most of this thread is not symmetrical.

NOr have your calculations included "Reciprocity". When reciprocity is applied do you claim a NET result? Yes or No.

3. Whether or not the 2 clocks record the same time depends on when they are started and stopped, obviously.

Obviously and one not only can but must specify simultaneity. It is ludricrus to claim a time dilation by claiming they are started or stopped at different times.

The arguement over simultaneity is a smoke screen that HAS been eliminated by my synchronization proceedure. which you failed miserably at trying to refute. Actually proving simultaenity infact is not even part of the jproblem it can and should be stipulated to do a fair and balanced evaaluation of Relativity. Not doing so is deliberate efforts to avoid addressing the issue.

4. For most of this thread, we have been discussing a situation where the clocks are not stopped simultaneously in at least one of the two frames.

Perhaps by you but not by me. Lets discuss my presentation and stop altering the playing field to post irrelevant BS.

5. My "admission" you are so proud of referred to a symmetical situation. I have posted that situation in detail previously.

And as I have pointed out including acceleration (non-inertial) data does NOT alter the conclusion as long as acceleration is applied to both clocks. When it is not applied to both clcoks, then yes there dan be a time shift but it is due to the non-linear portion of the test and there is still no net time shift due to relativie velocity itself. Your efforts to discuss symmetry in this sense is nothing but a smoke screen.

6. You confuse the two situations, just like you confuse everything else.

Poor confused MacM.

I am clearly not the one confused here.

You're raving.
And you are avoiding the issue.

Look at what I wrote, then look at your reply. Did I say that relativity does not hold? No. Did I say that each observer does not see himself at rest? No.

You're putting words into my mouth that I never said. You're in fantasy MacM la-la land.

Fine then apply that fact to your calculations and tell these folks having applied reciprocity that you still get net time dilation. You DO NOT.

Your fantasy may be easy to refute. My words are quite another matter.

You say it is easy to refute, then give a valid refutation.

No response, as usual. You don't answer because you can't answer.

This statement applies to yourself.[

quote]Waffle on, MacM. I know that nothing I say will make the slightest shade of difference in your fantasy land.[/QUOTE]

Only if you say something that is applicable to the issue which is a valid refutation and stop meandering all over the place with irrelevant horseshit.
 
James R said:
QQ:


It is very important when having discussions of physics to know or to learn the technical meanings of words. If you don't know, then you often miss important parts of physical reasoning, or you can misinterpret concepts.

This is one of MacM's major failings. He uses terms such as "reference frame", which sound technical, without actually knowing what they mean.

What a crock of crap. You cannot answer the issue and chose to make deformation your lance. HeHeHe. Glad I do not need such crutches.
 
Quantum Quack said:
This I think is the most important thing that has been said the entire thread...certainly for me any way.

The interesting thing i have been thinking is

If we take two objects A and B and place them in a void of nothing and they are separating at a speed of say 0.9c how are we to determine which has negative velocity.?

Do we arbitarilly choose one object over another or is there some other means that I can't see?


You are on the correct path. Now ask them to explain what differeance it makes in either case which velocity is given the - sign. NONE. When reciprocity is applied the mathematical conclusion is identical.
 
MacM said:
And I would assume you have posted what you think is a clear differance. Please advise readers that (-X)<sup>2</sup> = X<sup>2</sup>.

Or are you that inept to not understand that.

Because your knowledge of relativity is just that little. You don't even familiar with Lorentz's transformation. When come to LT, v or -v make the difference. Learn more mister, don't stuck with just one or two formulas...and particularly not the wrong TD. :D
 
Quantum Quack said:
the above I think is at the heart of the reciprication issue?


Just remember the mathematical rule you were taught in grade school. (-) * (-) = +.

Don't let this claim of precision in definiton alter your correct assumption that it doesn't alter the ultimate conclusion. It DOES NOT.
 
MacM said:
You are on the correct path. Now ask them to explain what differeance it makes in either case which velocity is given the - sign. NONE. When reciprocity is applied the mathematical conclusion is identical.

Try Lorentz's transformation once, you'll love it unless you like to live in your dream world as you are now.
 
Paul T said:
Try Lorentz's transformation once, you'll love it unless you like to live in your dream world as you are now.

I see you choose to not address the reciprocity issue either.
 
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