@Billy
I think that in discussion between us, there was a misunderstanding in the terms used. Initial discussion was about "own axial rotation" of the Moon and we have now reached to dissect the entire universe.
On me personally I am not interested to make math, to calculate durations, masses, forces or any other such things. I am just interested to comprehend mentally, to visualize the movements of the moon, the Earth and Sun. I would not have wanted to come to a contradiction in mathematics, but because you forced me to do this, I will do, but only limited and to show you that you are wrong, in those that affirm and sustain with your math.
The value of 206.25 is a report showing how many times is more powerful gravitational pull of the Sun compared to that of the Earth. It This value is not the force of attraction of the Sun exerted on the Moon. Not at all!
The value of the gravitational force of the Sun exerted upon the Moon is about twice higher than that exerted by the Earth upon the Monn, because the Sun is at a distance of about 400 times larger compared to the distance between Earth and Moon, and we all know that the gravitational force decrease with the inverse square of the distance. And no more words, are sufficient ones until now!
Below is a calculation that shows the true value of the gravitational pull exerted by the Sun and the Earth upon the Moon:
Mass of the earth: about 6 x 10^24 kg
Earth-moon distance: about 384,000 km
Mass of the sun: about 2 x 10^30 kg
Sun-moon distance: about 150,000,000 km
The sun's gravitational pull on the moon (Sm) is equal to
2 x 10^30 / (1.5 x 10^8)^2 =~ 8.8 x 10^13
The earth's gravitational pull on the moon (Em) is equal to
6 x 10^24 / (3.84 x 10^5) = ~ 4 x 10^13
Now, we have Sm / Em = 8.8 x 10^13 / 4 x 10^13 => Sm / Em = 2.2 => Sm = 2.2 Em => just about twice time higher that that exerted by the Earth upon the Moon, and in no event an amount as that obtained by you, that is 206.25 times higher than that of Earth.
I really don't like what I did now, but you forced me to make these calculations. These errors can be seen by anyone who check closely your math. I thought you correct yourself, this error. Sorry!
So, coming back to your last message, and to avoid any further misunderstanding, especially from myself, I would like to make a short analysis of the first image and I want to know if you agree with the fact that what we see in this image represent the real path followed by the moon on its orbit around the Sun. If the answer is yes, that means you agree with what I already said; that the Moon path is for 14 days concave wrt the Sun, and for other 14 days is concave wrt to the Sun. On the other hand, I can agree with your affirmation that the orbit of the Moon is everywhere concave toward the Sun, if we talk about an entire segment of the Moon orbit, or even the entire orbit (let's say a segment length of four phases of the Moon). Exactly as can be seen by anyone from that image. If you don't agree, please be patient and try to explain how you see the movement of the Monn being on a permanent concave path wrt the Sun. Maybe I can not understand this motion, or I understand differently the notion of convex-concave. Here is an image that I think it represent what I think you want to say about the concave path of the Moon around the Sun: h t t p://w w w .math.nus.edu.sg/aslaksen/pictures/o40.gif
Related to the second image, it is very well documented, but I don't understand this phrase "Such a path would always be concave to the sun, but close to the earth's orbit, crossing it twice a month.". I, on the contrary, I think this way, as being convex to the Sun! And if it intersect with the Earth, twice a month, that means, at least fro me, exactly what I said above (~14 days concave, and !14 days convex).
Anyway, after we will finish this, and we'll reach a common opinion, I would like to return to the initial discussion, the claims of Tesla, that the Moon has no own axial rotation movement, opinion that I totally agree.
@Tim
I can't answer to your messages due to limitations here on this forum. Also, I already opened an account on that forum you suggested me, but until today I did not received the confirmation email with activation link, and can't post anything there. Sorry! Stupid rules everywhere! But, be sure when I'll have the rights to post I'll answer to your questions.
I think that in discussion between us, there was a misunderstanding in the terms used. Initial discussion was about "own axial rotation" of the Moon and we have now reached to dissect the entire universe.
On me personally I am not interested to make math, to calculate durations, masses, forces or any other such things. I am just interested to comprehend mentally, to visualize the movements of the moon, the Earth and Sun. I would not have wanted to come to a contradiction in mathematics, but because you forced me to do this, I will do, but only limited and to show you that you are wrong, in those that affirm and sustain with your math.
The value of 206.25 is a report showing how many times is more powerful gravitational pull of the Sun compared to that of the Earth. It This value is not the force of attraction of the Sun exerted on the Moon. Not at all!
The value of the gravitational force of the Sun exerted upon the Moon is about twice higher than that exerted by the Earth upon the Monn, because the Sun is at a distance of about 400 times larger compared to the distance between Earth and Moon, and we all know that the gravitational force decrease with the inverse square of the distance. And no more words, are sufficient ones until now!
Below is a calculation that shows the true value of the gravitational pull exerted by the Sun and the Earth upon the Moon:
Mass of the earth: about 6 x 10^24 kg
Earth-moon distance: about 384,000 km
Mass of the sun: about 2 x 10^30 kg
Sun-moon distance: about 150,000,000 km
The sun's gravitational pull on the moon (Sm) is equal to
2 x 10^30 / (1.5 x 10^8)^2 =~ 8.8 x 10^13
The earth's gravitational pull on the moon (Em) is equal to
6 x 10^24 / (3.84 x 10^5) = ~ 4 x 10^13
Now, we have Sm / Em = 8.8 x 10^13 / 4 x 10^13 => Sm / Em = 2.2 => Sm = 2.2 Em => just about twice time higher that that exerted by the Earth upon the Moon, and in no event an amount as that obtained by you, that is 206.25 times higher than that of Earth.
I really don't like what I did now, but you forced me to make these calculations. These errors can be seen by anyone who check closely your math. I thought you correct yourself, this error. Sorry!
So, coming back to your last message, and to avoid any further misunderstanding, especially from myself, I would like to make a short analysis of the first image and I want to know if you agree with the fact that what we see in this image represent the real path followed by the moon on its orbit around the Sun. If the answer is yes, that means you agree with what I already said; that the Moon path is for 14 days concave wrt the Sun, and for other 14 days is concave wrt to the Sun. On the other hand, I can agree with your affirmation that the orbit of the Moon is everywhere concave toward the Sun, if we talk about an entire segment of the Moon orbit, or even the entire orbit (let's say a segment length of four phases of the Moon). Exactly as can be seen by anyone from that image. If you don't agree, please be patient and try to explain how you see the movement of the Monn being on a permanent concave path wrt the Sun. Maybe I can not understand this motion, or I understand differently the notion of convex-concave. Here is an image that I think it represent what I think you want to say about the concave path of the Moon around the Sun: h t t p://w w w .math.nus.edu.sg/aslaksen/pictures/o40.gif
Related to the second image, it is very well documented, but I don't understand this phrase "Such a path would always be concave to the sun, but close to the earth's orbit, crossing it twice a month.". I, on the contrary, I think this way, as being convex to the Sun! And if it intersect with the Earth, twice a month, that means, at least fro me, exactly what I said above (~14 days concave, and !14 days convex).
Anyway, after we will finish this, and we'll reach a common opinion, I would like to return to the initial discussion, the claims of Tesla, that the Moon has no own axial rotation movement, opinion that I totally agree.
@Tim
I can't answer to your messages due to limitations here on this forum. Also, I already opened an account on that forum you suggested me, but until today I did not received the confirmation email with activation link, and can't post anything there. Sorry! Stupid rules everywhere! But, be sure when I'll have the rights to post I'll answer to your questions.