Maths to explain time.

Discussion in 'Alternative Theories' started by amber, Feb 1, 2018.

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  1. origin Heading towards oblivion Valued Senior Member

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    The random symbol generator strikes again.

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  3. amber Registered Member

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    A mistake in presentation is not trolling. I have also explained the content in words, explaining that the change of time is equal to a change in state in entropy of a system. I am ''backing up'' Einsteins work and adding the physicality needed to time to completely cover relativity.
    The twin paradox would not be a paradox, twin 2 really did age less because time would be a quantifiable measurement directly proportional to the change of entropy. When the frequency of the caesium dilates in motion, this shows us a change in entropy, it is emitting radiation at a slower frequency.
     
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  5. amber Registered Member

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    Hows that random when its basic symbols?
     
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  7. Dywyddyr Penguinaciously duckalicious. Valued Senior Member

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    Misusing.

    Already explained.
    The units don't work out. The equation is meaningless. You haven't shown how you arrived at this equation.

    No, what I (and everyone else) is saying is the way you use them is gibberish and meaningless.

    And we should take your word it because...?

    Because S uses Kelvin in its units. Kelvin is temperature.

    Why do you believe this?

    No.
     
  8. amber Registered Member

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    I will agree with you that my maths is meaningless , so we can now ignore the maths and discuss the notion.

    Does time have physicality or is time no more than arbitrary?

    You can't have both sides of the coin facing up at the same time.
     
  9. DaveC426913 Valued Senior Member

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    The Notions subforum is two doors down, next to Free Thoughts.

    The reason we don't want to discuss notions is because they are word salad. Like the equation above, the notions are not based on a sound knowledge of science. Why get into a debate where the OP insists his idea must be right, when he doesn't even know what he doesn't know?

    Your best bet is to ask and learn.
     
  10. origin Heading towards oblivion Valued Senior Member

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    Basic symbols placed in random order - a random symbol generator!
     
  11. amber Registered Member

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    My incorrect equations were not randomly generated, if I had the correct equations for my notion then we would not be having this conversation. To me my equations say what I want them to say, but obviously the symbols of science use, I am using differently and they do not mean what I thought they meant.
     
  12. origin Heading towards oblivion Valued Senior Member

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    LOL, now that's funny. Good one...

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  13. DaveC426913 Valued Senior Member

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    Consider asking questions instead of insisting on being right. That will go a longer way.
     
  14. amber Registered Member

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    They obviously did not mean to what I thought they meant, an easy error. Will you please help me to correct them?
     
  15. amber Registered Member

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    Will you please help me to explain something in maths?


    I firstly want to state a change in time?
     
  16. DaveC426913 Valued Senior Member

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    This is not asking, this is telling.
     
  17. amber Registered Member

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    How is that telling? That's asking how do i state a change of time in math representation?
     
  18. DaveC426913 Valued Senior Member

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    Because you're just going to turn around and use it to advance your notion.

    A change in time is simply \(t_2-t_1\) or \(\Delta t\).
     
    Last edited: Feb 1, 2018
  19. origin Heading towards oblivion Valued Senior Member

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    Sure which symbols do you want defined?
     
  20. amber Registered Member

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    And delta is the triangle symbol?
     
  21. amber Registered Member

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    I want to define a change in entropy , so delta something?
     
  22. amber Registered Member

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    Delta t = ????
     
  23. DaveC426913 Valued Senior Member

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    = \(t_2-t_1\)

    What two times did you want to measure?

    The Δt for a 60 mile trip, at 60mph is \(t_2-t_1\) (for example) 2:57 - 1:57 = 1 hour.

    Or you could use it in a formula:

    Δt = 1/Δv
     
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