The tides are the result of the rotation of the Earth and the whirlpools

Quite often, airplanes move along the equator toward the moon and against the moon when the sun is at the top and the tidal force would be noticed by pilots on fuel consumption and flight time .
No. The difference is almost too small to measure; about one part per million.
The role of the moon is indirect, creating an uneven orbital velocity of the Earth ..
Correct, sort of. The system that is Earth and Moon orbit the Sun at the same speed. Since the center of rotation of that system is not the center of mass of the Earth, then there's a little increase and decrease of orbital speed as measured from the Earth. Again, almost too small to measure.
It is believed that the tidal forces stopped the rotation of the moon, and now it rotates synchronously. But there are more than 300 known satellites and why they all stopped at the same time and where did the force that rotated the satellites go ...
There are over 4000 man made satellites orbiting the Earth. None of them "stopped." (Other than the ones that re-entered, of course.)
If the "Lunar tidal current" existed, it would really quickly stop the rotation of the Earth, since enormous energy would be expended on the ebb and flow.
The Earth is gradually slowing down due, in part, to the attraction of the Moon on the sea and air. Eventually it will stop and become tidally locked to the Moon. Estimates for this are in the ten billion year range. So no worries in the near term.
Tidal forces today are successfully used as a plug from many secrets of nature.
But in fact, they exist only theoretically, and in practice, not a single gravimetric device recorded them.
Matt Jaffe and Holger Muller of UC Berkeley have in fact measured the effect of the Moon's tidal acceleration on free particles.
The acceleration of gravity at the equator is less than at the poles: at the equator is 978 Gal, and at the poles - 983 Gal.
There is no data on the fluctuation of tidal forces; if there were fluctuations, there would be data.
Here is some data for you:
When the Moon is overhead you feel 9.79999883 m/s^2 of gravity. When the Moon is beneath you you feel 9.80000111 m/2^2 of gravity. (Assuming you are in a place where the normal acceleration is 9.8 m/2^2.)

Do you feel better now that you have the data?
 
What??

You assert that 300 satellites all stopped their rotation at the same time?
Defend this.
A passing asteroid? Just a thought....:)

Seems to me that a stationary (non-rotating) satellite would be an advantage in reception and transmission. No need for constant adjustments. Maybe they build them to not rotate?
 
This theory has very good testability.
If high tides form on that bank where you are standing, it means that the current is moving fast along this bank.
It is easy to check based on a map of the sea currents that are on the Internet.
Approximately the tide chart will look like this:
1 km / h - 1 meter.
2 km / h - 2 meter.
3 km / h - 3 meter.
And so on.
And no philosophy.
 
This theory has very good testability.
If high tides form on that bank where you are standing, it means that the current is moving fast along this bank.
It is easy to check based on a map of the sea currents that are on the Internet.
Approximately the tide chart will look like this:
1 km / h - 1 meter.
2 km / h - 2 meter.
3 km / h - 3 meter.
And so on.
And no philosophy.

https://www.glerl.noaa.gov/res/glcfs/glcfs.php?lake=o&ext=sfcur&type=N&hr=27

So you're telling me that in Lake Ontario - where currents can reach 4km/h (2 knots) - we should be seeing tides in excess of 14 feet???

I'd say yep - it's been tested - and failed.
 
This theory has very good testability.
If high tides form on that bank where you are standing, it means that the current is moving fast along this bank.
Incorrect. If you think that, you have a very fundamental understanding of what a tide is.

If the Earth was tidelocked to the Moon you would have a permanent high tide in two locations. If you were near those locations the tide would be high near you, forever. No currents.
No philosophy.
And no science either, apparently.
 
This theory has very good testability.
If high tides form on that bank where you are standing, it means that the current is moving fast along this bank.
It is easy to check based on a map of the sea currents that are on the Internet.
Approximately the tide chart will look like this:
1 km / h - 1 meter.
2 km / h - 2 meter.
3 km / h - 3 meter.
And so on.
And no philosophy.
And round and round the merry goes around

Even though it doesn't work

:)
 
This theory has very good testability.
If high tides form on that bank where you are standing, it means that the current is moving fast along this bank.
It is easy to check based on a map of the sea currents that are on the Internet.
Approximately the tide chart will look like this:
1 km / h - 1 meter.
2 km / h - 2 meter.
3 km / h - 3 meter.
And so on.
And no philosophy.
The amplitude of the tides also depends on the size of the whirlpools, the amount of water under the whirlpool, the distance from the coast to the whirlpool, and the direction of flow (to the west, east, north, south).
 
The only way to refute the whirlpool theory of tides is to name the coast where the current is moving fast, but there are no high tides there.
 
The only way to refute the whirlpool theory of tides is to name the coast where the current is moving fast, but there are no high tides there.
Sure. The Florida coast. Very average tides - but a strong continuous current that does not depend on tides.
============
Florida Current
Beginning in the Caribbean and ending in the northern North Atlantic, the Florida Current leading into the Gulf Stream is a north flowing ocean current that reaches speeds in excess of 2.0m/s, particularly in the Florida Current region closest to the USA’s eastern seaboard.

http://www.oceanflowenergy.com/ocean-currents.html
============
 
The only way to refute the whirlpool theory of tides is to name the coast where the current is moving fast, but there are no high tides there.
I did.

Lake Ontario.

Your idea predicts fourteen foot tides in Rochester Harbour.
Rochester Harbour, in fact, has insignificant tides.
 
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